Answer:
NaOH is the limiting reactant and MgCl2 is in excess.
Explanation:
let's calculate the mole of each reactant.
number of moles of MgCl2 =
number of moles of NaOH =
as per the reaction , 1 mol of Magnesium choloride reacts with 2 moles of NaOH
hence 0.01926 needs 0.01926x2= 0.03852 moles of NaOH , but there are only 0.0282 moles of NaOH available .
Fusion reaction is a type of nuclear reaction where two or more nuclei combine or collide to form an element with a higher atomic number. This happens when the collision is in a very high speed. In this process, some of the matter of the fusing nuclei is converted to photons.
Answer:
Here's what I get
Explanation:
The three resonance forms of N₂O are shown in the first diagram below (you can also use horizontal dashes to represent the bonding pairs).
To get the formal charge (FC) on the atoms, cut each bond in half, as in the second diagram.
Each atom gets the electrons on its side of the cut.
Formal charge = valence electrons in isolated atom - electrons on bonded atom
FC = VE - BE
(a) In Structure A
Left-hand N:
VE = 5
BE = 1 lone pair (2)+ 3 bonding electrons = 2 + 3 = 5
FC = 5 - 5 = 0.
Central N:
VE = 5
BE = 4
FC = 5 - 4 = +1
On O:
VE = 6
BE = 3 lone pairs(6) + 1 bonding electron = 7
FC = 5 - 6 = -1
(b) In Structure B
Left-hand N:
VE = 5
BE = 2 lone pairs (4)+ 2 bonding electrons = 4 + 2 = 6
FC = 5 - 6 = -1.
Central N:
VE = 5
BE = 4
FC = 5 - 4 = +1
On O:
VE = 6
BE = 2 lone pairs(4) + 2 bonding electrons = 6
FC = 6 - 6 = 0
(c) In Structure C
Left-hand N:
VE = 5
BE = 3 lone pairs (6)+ 1 bonding electrons = 6 + 1 = 7
FC = 5 - 7 = -2.
Central N:
VE = 5
BE = 4
FC = 5 - 4 = +1
On O:
VE = 6
BE = 1 lone pair(2) + 3 bonding electrons = 5
FC = 6 - 5 = +1
Answer:
The Phosphorylated glucose(glucose +inorganic phosphate), with the energy supplied from ATP hydrolysis formed glucose 6- phosphate, which is later converted to 2 molecules of fructose 6-phosphate- this is phosphorylation.And represented the fate of glucose -6-phosphate.
The fructose 6-phosphate are converted to triose phosphate- which is a 2-molecules of 3C compound. The latter is oxidized by NAD→ NADH+ to form intermediates in the glycolytic pathways .
These intermediates are converted to ribose 5-phosphates in the presence of transketolase and transaldolase enzymes.And they are finally converted to pyruvate in the glycolytic pathway with the production of 2ATPs per molecule of glucose.
Basically the phosphate pathway reaction is very slow due to enzyme catalysis.
Data:
V1 (initial volume) = 233 mL
P1 (initial pressure) = 622 kPa
V2 (final volume) = ? (mL)
P2 (final pressure) = 988 kPa
Formula:
P1 * V1 = P2 * V2
Solving:
P1 * V1 = P2 * V2
622 * 233 = 988 * V2
114926 = 988 V2
988 V2 = 114926