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3 years ago

The data set below has an outlier.

2 answers:

4 0

Data set: <span>2, 10, 10, 11, 11, 12, 12, 12, 13, 14, 14
</span>
range: 14 - 2 = 12
median: 12
lower quartile = 10
interquartile range = 4

Data set w/o outlier 2: <span>10, 10, 11, 11, 12, 12, 12, 13, 14, 14

range: 14 - 10 = 4
median: 12
lower quartile: 10.5
interquartile range = 3.5

The value that change the most by removing the outlier is A.) THE RANGE.</span>

Anton [14]3 years ago

4 0

To answer the problem above, we must define what an outlier is. An outlier is a number in a set of data that is smaller or larger than the rest of the data. In this problem, the outlier is 2. To know which value changed the most we solve each with and without the outlier.
A. range: 12(with), 4(without)
B. median: 12 (with), 12 (without)
C. lower quartile: 10.5(with), 11(without)
D. interquartile range: 2(with), 2(without)

The answer is A. range.

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Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that

RUDIKE [14]

The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 $(x+4)^{2}$ /2!+...........

Given a function f(x)=9/x,a=-4.

We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.

The taylor series of a function f(x)= $f(a)+f^{1}(a)(x-a)/1!+ f^{11}(a)(x-a)^{2} /2! +f^{111}(a)(x-a)a^{3}/3!+..........$

Where the terms in f prime $f^{1}$ (a) represent the derivatives of x valued at a.

For the given function.f(x)=8/x and a=-4.

So,f(a)=f(-4)=8/(-4)=-2.

$f^{1}$ (a)= $f^{1}$ (-4)=-8/( $-4)^{2}$

=-8/16

=-1/2

The series of f(x) is as under:

f(x)=f(-4)+ $f^{1}(-4)(x+4)/1!+ f^{11}(-4)(x+4)^{2}/2!.............$

$=8/(-4)-8/(-4)^{2} (-4)(x+4)/1!+ 24/(-4)^{3} (-4)(x+4)^{2}/2!.............$

=-2+2(x+4)/1!-24/16 $(x+4)^{2}$ /2!+...........

Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 $(x+4)^{2}$ /2!+...........

Learn more about taylor series at brainly.com/question/23334489

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3 0

1 year ago

A fruit seller has 3 crates of apples. Each crate has 100 apples. If he packed 6 apples in 1 box. Which of these gives the numbe

xz_007 [3.2K]

Answer:

300 divided by 6

Step-by-step explanation:

Given that;

Number of crates of apple owned by fruit seller = 3 crates

Number of apples in each crate = 100 apples

He packed 6 apples in 1 box;

Unknown:

Number of boxes needed to pack all the apples = ?

This problem is pretty straight forward;

Number boxes needed to pack all apples = $\frac{Number of crates owned by fruit seller x number of apples per crate}{Number of apples per box}$

Input the parameters and solve;

Number of boxes need to pack all apples = $\frac{100 x 3}{6}$ = $\frac{300}{6}$

So the solution is 300 divided by 6

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3 years ago

4 times what number gives you 24

VashaNatasha [74]

6x4 = 24
Therefore, 24 is your answer.

8 0

3 years ago

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Describe the relationship between the values of the independent and dependent variables (plz help)

Vadim26 [7]

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3 years ago

Merrill bought m notebooks for $2.50 each and n pens for $1.25 each. Which expression best shows how much she spent?

kati45 [8]

Answer:

2.50m+1.25n

Step-by-step explanation:

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2 years ago