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exis [7]
3 years ago
7

The data set below has an outlier.

Mathematics
2 answers:
nika2105 [10]3 years ago
4 0
Data set: <span>2, 10, 10, 11, 11, 12, 12, 12, 13, 14, 14
</span>
range: 14 - 2 = 12
median: 12
lower quartile = 10
interquartile range = 4

Data set w/o outlier 2: <span>10, 10, 11, 11, 12, 12, 12, 13, 14, 14

range: 14 - 10 = 4
median: 12
lower quartile: 10.5
interquartile range = 3.5

The value that change the most by removing the outlier is A.) THE RANGE.</span>
Anton [14]3 years ago
4 0
To answer the problem above, we must define what an outlier is. An outlier is a number in a set of data that is smaller or larger than the rest of the data. In this problem, the outlier is 2. To know which value changed the most we solve each with and without the outlier.
A. range: 12(with), 4(without)
B. median: 12 (with), 12 (without)
C. lower quartile: 10.5(with), 11(without)
D. interquartile range: 2(with), 2(without)

The answer is A. range.
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Can you help me please help me
pashok25 [27]

Answer:

I can`t really see the question that well, but if I understand correctly here`s the first few.

1. Subtraction

2. Addition

3. Addition

4. Subtraction

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6. Subtraction

It looks like its asking what is happening in those situations (is the number being added or subtracted). Sorry if that`s not much help

4 0
3 years ago
Jaron walked 15 blocks north and then 3 blocks west to school. Marisol walked 3 blocks east and then 15 blocks south to school.
Svet_ta [14]

Answer:

sqrt(15² + 3²) = sqrt(15² + 3²)

Step-by-step explanation:

Using Pythagoras:

15 blocks North = 15 blocks south (direction opposite to each other)

3 blocks west = 3 blocks east (directions opposite to each other)

Hence distance traveled (d) :

JARON

D = sqrt(15² + 3²)

MARISOL:

D = sqrt(15² + 3²)

Hence ;

sqrt(15² + 3²) = sqrt(15² + 3²)

5 0
3 years ago
a group of friends are hiking on trail y when they reach an intersection with trail x. Trail x is perpendicular to trail y. If t
shusha [124]
I have the same question on a test I'm taking thanks
8 0
3 years ago
Which do you pick and why? How much money do you end up with in each case?
Mademuasel [1]

Answer:

1. Start with $1 and then double the money you have everyday for 30 days. You would end up with 1,073,741,824 on the 30th day.

Step-by-step explanation:

Why you should choose the first option:

1 x 2 = 2

2 x 2 = 4

4 x 2 = 8

8 x 2 = 16

16 x 2 = 32

32 x 2 = 64

64 x 2 = 128

128 x 2 = 256

256 x 2 = 512

512 x 2 = 1024

1024 x 2 = 2048

2048 x 2 = 4096

4096 x 2 = 8192

8192 x 2 = 16384

16384 x 2 = 32768

32768 x 2 = 65536

65536 x 2 = 131072

131072 x 2 = 262144

262144 x 2 = 524288

524288 x 2 = 1048576

1048576 x 2 = 2097152

2097152 x 2 = 4194304

4194304 x 2 = 8388608

8388608 x 2 = 16777216

16777216 x 2 = 33554432

33554432 x 2 = 67108864

67108864 x 2 = 134217728

134217728 x 2 = 268435456

268435456 x 2 = 536870912

536870912 x 2 = 1073741824

7 0
3 years ago
If triangle ABC defined by the coordinates A(1,1), B(9,1), C(1,9) is dilated by a scale factor of 1/2
alukav5142 [94]

Answer:

The transformed points of the triangle ABC are A' (x,y) = \left( \frac{1}{2}, \frac{1}{2}\right), B'(x,y) = \left(\frac{9}{2}, \frac{1}{2} \right), C'(x,y) = \left(\frac{1}{2}, \frac{9}{2}\right)

Step-by-step explanation:

The new points after applying the scale factor are, respectively:

A' (x,y) = \frac{1}{2}\cdot (1,1)

A' (x,y) = \left( \frac{1}{2}, \frac{1}{2}\right)

B' (x,y) = \frac{1}{2}\cdot (9,1)

B'(x,y) = \left(\frac{9}{2}, \frac{1}{2} \right)

C'(x,y) = \frac{1}{2}\cdot (1,9)

C'(x,y) = \left(\frac{1}{2}, \frac{9}{2}\right)

7 0
3 years ago
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