All categories

3 years ago

If f(x)=x2 and g(x)=|x| find the following functions. 1. f+g 2. f-g 3. fg

Mathematics

1 answer:

marusya05 [52]3 years ago

5 0

Answer:

1. x^2 + (absolute value) X

2. x^2 - (absolute value) X

3. x^2 * (absolute value) X

Step-by-step explanation:

Add equations for 1.

Subtract equations for 2.

Multiply equations for 3.

You might be interested in

6-11x=7x-12 how do you solve

tekilochka [14]

Use Cymath it helps and give u the answer

6 0

4 years ago

3^x+2=8^x-1 Solve for x.

zubka84 [21]

I assume the equation is supposed to be

$3^{x+2}=8^{x-1}$

Then we can write

$9\cdot3^x=\dfrac18\cdot8^x\implies\left(\dfrac38\right)^x=\dfrac1{72}$

Take the logarithm of base 3/8 on both sides:

$\log_{3/8}\left(\dfrac38\right)^x=\log_{3/8}\dfrac1{72}$

$\implies x\log_{3/8}\dfrac38=-\log_{3/8}72$

$\implies x=-\log_{3/8}72$

- - -

If the equation is actually $3^x+2=8^x-1$ , I'm afraid it cannot be solved exactly.

5 0

3 years ago

-\frac{4\left(x+3\right)}{5}=4x-12

Keith_Richards [23]

Answer:

huh

Step-by-step explanation:

6 0

3 years ago

If you flip a pair of coins 48 times, how many times are you most likely to get 2 heads.

pentagon [3]

But actually its based on your luck

3 0

3 years ago

What are the possible lengths for x, the third side of a triangle, if two sides are 21 and 10

SashulF [63]

To solve we need to use Pythagoras theorem ( $a^{2} + b^{2} = c^{2}$ )

There are 2 possible lengths for x: hypotenuse or one of the 2 shorter sides.

Hypotenuse:
10^{2} + 21^2 = $x^{2}$
100+441= $x^{2}$
$\sqrt{541} = \sqrt{ x^{2} }$
23.3≈x

Shorter leg:
$10^2 + x^2=21^2$
$x^2= 21^2-10^2$
$x^{2}$ = 441-100
$\sqrt{ x^{2} } = \sqrt{341}$
x≈18.47

8 0

3 years ago

If f(x)=x2 and g(x)=|x| find the following functions. 1. f+g 2. f-g 3. fg​

If f(x)=x2 and g(x)=|x| find the following functions. 1. f+g 2. f-g 3. fg