1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vinil7 [7]
3 years ago
13

A substance that forms a vapor is generally in what physical state at room temperature? solid gas liquid or solid liquid

Chemistry
2 answers:
Lena [83]3 years ago
7 0

Answer: dry ice

Explanation:

Normally in gas but a few exceptions can be made for liquid and solid. A rare example of liquid is boiling water, and a rare example for solid is dry ice.

Anit [1.1K]3 years ago
3 0

Answer:

solid gas liquid

Explanation:

solid liquid can never form a vapor

You might be interested in
Calculate the grams of ethane present in a sample containing 0.4271 moles if the molar mass of ethane is 30.067 g/mol.
adelina 88 [10]

The grams of ethane present in a sample containing 0.4271 mole is 12.84 g

<h3>Description of mole </h3>

The mole of a substance is related to it's mass and molar mass according to the following equation

Mole = mass / molar mass

With the above formula, we can obtain the mass of ethane. Details below

<h3>How to determine the mass of ethane</h3>

The following data were obtained from the question:

  • Mole of ethane = 0.4271 mole
  • Molar mass of ethane = 30.067 g/mol
  • Mass of ethane =?

The mass of ethane present in the sample can be obtained as follow:

Mole = mass / molar mass

Cross multiply

Mass = mole × molar mass

Mass of ethane = 0.4271 × 30.067

Mass of ethane = 12.84 g

Learn more about mole:

brainly.com/question/13314627

#SPJ1

5 0
1 year ago
What is the electron configuration for 1s2 2s2 2p6 3s2 3p6​
Sliva [168]
This is going to lead you to the element Argon. Is this what you are asking?
7 0
2 years ago
Gaseous methane (CH4) reacts with gaseous oxygen gas (02) to produce gaseous carbon dioxide (CO2) and gaseous water (H20). What
Mariana [72]

Answer:

Theoretical yield = 3.51 g

Explanation:

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

For CH_4  :-

Mass of CH_4  = 1.28 g

Molar mass of CH_4  = 16.04 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{1.28\ g}{16.04\ g/mol}

Moles_{CH_4}= 0.0798\ mol

For O_2  :-

Mass of O_2  = 10.1 g

Molar mass of O_2  = 31.998 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{10.1\ g}{31.998\ g/mol}

Moles_{O_2}= 0.3156\ mol

According to the given reaction:

CH_4+2O_2\rightarrow CO_2+2H_2O

1 mole of methane gas reacts with 2 moles of oxygen gas

0.0798 mole of methane gas reacts with 2*0.0798 moles of oxygen gas

Moles of oxygen gas = 0.1596 moles

Available moles of oxygen gas = 0.3156 moles

<u>Limiting reagent is the one which is present in small amount. Thus, CH_4 is limiting reagent. </u>

The formation of the product is governed by the limiting reagent. So,

1 mole of methane gas on reaction produces 1 mole of carbon dioxide.

0.0798 mole of methane gas on reaction produces 0.0798 mole of carbon dioxide.

Mole of carbon dioxide = 0.0798 mole

Molar mass of carbon dioxide = 44.01 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.0798\ moles= \frac{Mass}{44.01\ g/mol}

Mass of CO_2 = 3.51 g

<u> Theoretical yield = 3.51 g</u>

3 0
3 years ago
pleaaase help me asaaap for 150 points my insta is niqsariot_1 dm me for the other 50 points and pleasee answer all of the quest
liq [111]

Answer:

Just here for the points sorry

Explanation:

Minecraft I will not be able to make the weekend of this trip until Sunday evening and I will be away for the rest of the of the week weekend and I will will be back from London tomorrow for lunchtime a week or so if to for for if to go for the it a the the it a couple of rest in the morning the other week night if and time as I we are have the first one in the evening morning so I'll we have an appointment early for in a the class morning and for and then

6 0
3 years ago
Stalactites and stalagmites form as ________ precipitates out of the water evaporating in underground caves.
Fittoniya [83]

Stalactites and stalagmites form as ________ precipitates out of the water evaporating in underground caves.

Group of answer choices

hydrochloric acid

sodium bicarbonate

calcium carbonate

sodium chloride

sodium hydroxide

Answer:

calcium carbonate

Explanation:

A stalactite is an icicle-looking mould that is formed by the precipitation of natural minerals as a result of water dripping from the ceiling, hanging from a cave.

A stalagmites in the other hand, grows upwards and is also a mound that is formed by the deposits of minerals gotten by the water dripping on the floor of a cave.

Therefore, stalactites and stalagmites form as calcium carbonate precipitates out of the water evaporating in underground caves.

4 0
2 years ago
Other questions:
  • Write the balanced equation for each of the following changes and identify whether heat is a product or needed to start the reac
    14·1 answer
  • How many moles is 1.81 x 10^24 atoms of carbon?
    9·1 answer
  • 2. What are the similarities between law of triads and law of octaves?​
    10·1 answer
  • What is volume (chemistry definition)
    13·1 answer
  • Most carbon compounds are formed by exchanging electrons with carbon.<br> True<br> False
    7·2 answers
  • Which of the following are changing when a change of state is occurring?
    12·1 answer
  • which would you think would be a stronger interaction and why: an interaction between a sodium ion and the prtial negative charg
    6·1 answer
  • Given the following equation: CH4 + 202 CO2 + 2H2O
    7·2 answers
  • Which diagram represents an electrically neutral atom​?
    12·2 answers
  • Migration can best enhance the survival of individuals because it
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!