1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nadya68 [22]
3 years ago
14

What are some ways that use physics in your everyday life?

Chemistry
1 answer:
Gwar [14]3 years ago
3 0

Answer:

Roasting s'mores over a fire.

Ironing the wrinkles out of my shirts.

Wet clothes are dried with the hot air of the dryer.

Small speakers in your headphones use electricity and moving magnets to create sound waves.

Explanation:

You might be interested in
What test was used to identify hydrogen gas? Write a balanced equation to represent the test?
const2013 [10]
Burning splint test
2H2 (g) + O2 (g) -> 2H20 (g) + heat
It’s a combustion reaction
6 0
2 years ago
he rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy . If the rate c
Leya [2.2K]

The question is incomplete, here is the complete question:

The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy Ea = 71.0 kJ/mol . If the rate constant of this reaction is 6.7 M^(-1)*s^(-1) at 244.0 degrees Celsius, what will the rate constant be at 324.0 degrees Celsius?

<u>Answer:</u> The rate constant at 324°C is 61.29M^{-1}s^{-1}

<u>Explanation:</u>

To calculate rate constant at two different temperatures of the reaction, we use Arrhenius equation, which is:

\ln(\frac{K_{324^oC}}{K_{244^oC}})=\frac{E_a}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_{244^oC} = equilibrium constant at 244°C = 6.7M^{-1}s^{-1}

K_{324^oC} = equilibrium constant at 324°C = ?

E_a = Activation energy = 71.0 kJ/mol = 71000 J/mol   (Conversion factor:  1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

T_1 = initial temperature = 244^oC=[273+244]K=517K

T_2 = final temperature = 324^oC=[273+324]K=597K

Putting values in above equation, we get:

\ln(\frac{K_{324^oC}}{6.7})=\frac{71000J}{8.314J/mol.K}[\frac{1}{517}-\frac{1}{597}]\\\\K_{324^oC}=61.29M^{-1}s^{-1}

Hence, the rate constant at 324°C is 61.29M^{-1}s^{-1}

8 0
3 years ago
KBr(aq) + NaCl(aq) =
torisob [31]
It’s ionic
KCl(at)
Potassium chloride
7 0
3 years ago
How many grams of O are in 675 g of Na2O
PIT_PIT [208]
I think it is .00005815
6 0
3 years ago
The Group 1B metals, Cu, Ag, and Au, are called coinage metals. What chemical properties make them especially suitable for makin
notka56 [123]

Answer:

Explanation:

Coinage metals -

The group 11 elements , i.e. , Copper , Silver , Gold are called the coinage metals .

These metals are quite soft and can be easily molded to form coins . This property is called as the property of malleability .

And due its soft nature , it can easily be used to make jewelry ,

Since , making jewels require the metal to be soft and flexible ,

Hence , gold is suited the best for this .

4 0
3 years ago
Other questions:
  • It took 4.5 minutes for 1.0 l helium to effuse through a porous barrier. how long will it take for 1.0 l cl2 gas to effuse under
    5·1 answer
  • What is the ph of a 4.8 m pyridine solution that has kb = 1.9 × 10-9? the equation for the dissociation of pyridine is?
    15·2 answers
  • Identify the elemant that is a nonmetal , a gas, and has an element symbol that starts with the letter a
    7·1 answer
  • What is the formula of zinc sulphate?​
    6·2 answers
  • Balance the chemical equation below using the smallest possible whole number stoichiometric coefficients NH3(g) + O2(g) + CH4(g)
    13·1 answer
  • Identify which two compounds below are constitutional isomers
    6·1 answer
  • AM TWELVE AND A BOY TELL ME YOUR AGE AND IF YOUR SINGLE AND MY AGE WE CAN DATE<br> :)
    8·2 answers
  • What volume in milliliters of 0.100 M HCIO3 is required to neutralize<br> 40.0 mL of 0.165 M KOH?
    6·1 answer
  • What cause a mass defect?
    15·2 answers
  • the proposal that matter, like light, has wave properties in addition to particle properties was chegg
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!