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postnew [5]
3 years ago
15

Suppose that a fictitious element, x, has two isotopes: 59x (59.015 amu) and 62x (62.011 amu). the lighter isotope has an abunda

nce of 71.7%. calculate the atomic mass of the element x.
Chemistry
1 answer:
professor190 [17]3 years ago
4 0

The atomic mass of the element would simply be equal to the sum of the weighted average of each isotope, that is:

atomic mass = 59.015 amu * 0.717 + 62.011 amu * (1 – 0.717)

<span>atomic mass = 59.863 amu</span>

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PLEASE ANSWER <br> ARE THESE CORRECTTTTTT
Naddik [55]

1. The answer is E.

2. I agree with your answers.

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3 0
3 years ago
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____ 26. what is the weight percentage of nitrogen in urea, cn2h4o
Paraphin [41]
Weight percentage of nitrogen can be calculated using the following rule:
weight percentage of nitrogen = (weight of nitrogen / weight of urea) x 100

From the periodic table:
molecular mass of carbon = 12 grams
molecular mass of nitrogen = 14 grams
molecular mass of hydrogen = 1 grams
molecular mass of oxygen = 16 grams

therefore:
mass of nitrogen in urea = 2(14) = 28 grams
mass of urea = 12 + 2(14) + 4(1) + 16 = 60 grams

Substitute with the masses in the equation to get the percentage:
weight percentage of nitrogen = (28/60) x 100 = 46.667%
7 0
3 years ago
If Matteo has a model car with a volume of 100 mL and a mass of 200 g, what is the density of their model car?
OLEGan [10]

Answer:

<h2>2 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question we have

density =  \frac{200}{100}  \\

We have the final answer as

<h3>2 g/mL</h3>

Hope this helps you

6 0
3 years ago
Describe the many different forms of energy involved with stretching and releasing a rubber band. What other processes are simil
Nadya [2.5K]

Answer:

Conversion of kinetic energy to potential energy (chemo mechanical energy)

In the state of rest, the rubber is a tangled mass of long chained cross-linked polymer that due to their disorderliness are in a state of increased entropy. By pulling on the polymer, the applied kinetic energy stretches the polymer into straight chains, giving them order and reducing their entropy. The stretched rubber then has energy stored in the form of chemo mechanical energy which is a form of potential energy

Conversion of the stored potential energy in the stretched to kinetic energy

By remaining in a stretched condition, the rubber is in a state of high potential energy, when the force holding the rubber in place is removed, due to the laws of thermodynamics, the polymers in the rubber curls back to their state of "random" tangled mass releasing the stored potential energy in the process and doing work such as moving items placed in the rubber's path of motion such as an object that has weight, w then takes up the kinetic energy 1/2×m×v² which can can result in the flight of the object.

Explanation:

5 0
3 years ago
Read 2 more answers
A student finds a container of gases in the laboratory classroom with a total pressure reading of 655 mmHg. The label on the con
Elena-2011 [213]

Answer:

70.8 mmHg

Explanation:

To find partial pressure of carbon dioxide we first find the mole fraction of carbon dioxide

n (carbon dioxide) = 5/44.01 g/mol = 0.11361 mol

n (Helium) = 3.75 g/4 g/mol = 0.9375 mol

The partial pressure of carbon dioxide will be the mole fraction of carbon dioxide multiplied by the total pressure

Partial pressure = 0.11361g/(0.11361g + 0.9375 g)* 655 mmHg

                          = 70.8 mmHg

6 0
4 years ago
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