1. The answer is E.
2. I agree with your answers.
3. I also agree with your answers
Weight percentage of nitrogen can be calculated using the following rule:
weight percentage of nitrogen = (weight of nitrogen / weight of urea) x 100
From the periodic table:
molecular mass of carbon = 12 grams
molecular mass of nitrogen = 14 grams
molecular mass of hydrogen = 1 grams
molecular mass of oxygen = 16 grams
therefore:
mass of nitrogen in urea = 2(14) = 28 grams
mass of urea = 12 + 2(14) + 4(1) + 16 = 60 grams
Substitute with the masses in the equation to get the percentage:
weight percentage of nitrogen = (28/60) x 100 = 46.667%
Answer:
<h2>2 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula

From the question we have

We have the final answer as
<h3>2 g/mL</h3>
Hope this helps you
Answer:
Conversion of kinetic energy to potential energy (chemo mechanical energy)
In the state of rest, the rubber is a tangled mass of long chained cross-linked polymer that due to their disorderliness are in a state of increased entropy. By pulling on the polymer, the applied kinetic energy stretches the polymer into straight chains, giving them order and reducing their entropy. The stretched rubber then has energy stored in the form of chemo mechanical energy which is a form of potential energy
Conversion of the stored potential energy in the stretched to kinetic energy
By remaining in a stretched condition, the rubber is in a state of high potential energy, when the force holding the rubber in place is removed, due to the laws of thermodynamics, the polymers in the rubber curls back to their state of "random" tangled mass releasing the stored potential energy in the process and doing work such as moving items placed in the rubber's path of motion such as an object that has weight, w then takes up the kinetic energy 1/2×m×v² which can can result in the flight of the object.
Explanation:
Answer:
70.8 mmHg
Explanation:
To find partial pressure of carbon dioxide we first find the mole fraction of carbon dioxide
n (carbon dioxide) = 5/44.01 g/mol = 0.11361 mol
n (Helium) = 3.75 g/4 g/mol = 0.9375 mol
The partial pressure of carbon dioxide will be the mole fraction of carbon dioxide multiplied by the total pressure
Partial pressure = 0.11361g/(0.11361g + 0.9375 g)* 655 mmHg
= 70.8 mmHg