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Vaselesa [24]
3 years ago
14

When the volume of a gas is changed from 524 cm^3 to ____ cm^3, the temperature will change from 491 K to 297 K .

Chemistry
2 answers:
SpyIntel [72]3 years ago
5 0
V1/T1=V2/T2
524 cm^3/491 K =V2/297K

V2=(524 cm^3*297K)/491 K= 317K
Naily [24]3 years ago
4 0

Answer : The final volume of a gas is, 316.96cm^3

Explanation :

According to the Charles's law, the volume of a gas is directly proportional to the temperature of the gas at constant pressure and the number of moles of gas.

V\propto T

or,

\frac{V_1}{V_2}=\frac{T_1}{T_2}

where,

V_1 = initial volume of gas = 524cm^3

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 491 K

T_2 = final temperature of gas = 297 K

Now put all the given values in the above formula, we get the final volume of a gas.

\frac{524cm^3}{V_2}=\frac{491K}{297K}

V_2=316.96cm^3

Therefore, the final volume of a gas is, 316.96cm^3

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Determine whether each phrase describes carboxylic acids or esters.
Thepotemich [5.8K]

Answer:

Carboxylic acids produce hydrogen bonds amongst themselves and possess lower vapor pressure. They generally possess a sour odor. When an acid and a base react with each other to produce salt and water and comprises the combination of hydrogen and hydroxide ions, the reaction is termed the neutralization reaction. Thus, when carboxylic acid reacts with base the reaction is termed neutralization.

On the other hand, esters are known for their pleasant fragrances. They do not produce hydrogen bonds amongst themselves and possess higher vapor pressure. A hydration reaction in which free hydroxide dissociates the ester bonds between the glycerol and fatty acids of a triglyceride, leading to the formation of free fatty acids and glycerol is termed saponification.

Thus, the given blanks can be filled with carboxylic acid, carboxylic acid, esters, esters, esters, and carboxylic acid.

8 0
2 years ago
why are experimental investigations the best type of scientific investigation to demonstrate cause and effect relationships
Lelu [443]
Because they are coming from the ground and always safe
8 0
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What needs to be considered in balancing redox reactions?
Degger [83]
Number D both H and OH ions
8 0
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4. Calculate the final concentration if water is added to 1.5 L of a 12 M
konstantin123 [22]

Answer:

6M

Explanation:

(Molarity x Volume)concentrated soln = (Molarity x Volume)diluted doln

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6 0
3 years ago
A solution contains 0.140 mol KCl in 2.100 L water. What is the concentration of KCl in g/L?
viva [34]
<h3><u>Answer</u>;</h3>

≈ 4.95 g/L

<h3><u>Explanation;</u></h3>

The molar mass of KCl = 74.5 g/mole

Therefore; 0.140 moles will be equivalent to ;

 = 0.140 moles × 74.5 g/mole

 = 10.43 g

Concentration in g/L

   = mass in g/volume in L

   = 10.43/2.1

   =  4.9667

<h3>   <u> ≈ 4.95 g/L</u></h3>
4 0
3 years ago
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