Answer:
Given, 0.29 g of hydrocarbon produces 448ml of CO2 at STP. then, C2H5 is the emperical formula of hydrocarbon . n = 2 , hence, molecular formula will be C4H10
Answer:
Using cobalt glass could be helpful to identify elements that weakly emit blue and/or violet.
Explanation:
Answer:
Xe:[Kr]4d¹⁰5(sp³d³)₆⁺² => Octahedral Geometry (AX₆)⁺²
Explanation:
Xe:[Kr]4d¹⁰(5s²5p₋₁²p₀²p₁²5d₋₂d₋₁d₀)⁺² => Xe[Kr]5(sp³d³)₆²
Ca. #Valence e⁻ = Xe + 6F - 2e⁻ = 1(8) + 6(7) - 2 = 48
Ca. #Substrate e⁻ = 6F = 6(8) = 48
#Nonbonded free pairs e⁻ = (V - S)/2 = (48 - 48)/2 = 0 free pairs
#Bonded pairs e⁻ = 6F substrates = 6 bonded pairs
BPr + NBPr = 6 + 0 = 6 e⁻ pairs => Geometry => [AX₆]⁺² => Octahedron
Xe:[Kr]4d¹⁰(5s²5p₋₁²p₀²p₁²5d₋₂d₋₁d₀)⁺² => Xe[Kr]5(sp³d³)₆⁺²
XeF₆⁺² => 6(sp³d³) hybrid orbitals => Octahedral Geometry (AX₆)
Answer:
Separation technique used to separate mud and water without heating:
<u>Sedimentation-Decantation</u>
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Explanation:
<em>1.The settling of the heavier particle at the bottom when the container is left undisturbed is called </em><u><em>sedimentation.</em></u>
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<u><em>In a mixture of Mud and water :</em></u>
In this process the heavy mud particles settle at the bottom due to their high density .
2. Decantation : It is the process of pouring out the upper clear layer of the light particles.
<u><em>In a mixture of Mud and water :</em></u>
The water is lighter and form a clear layer over the settled mud particles. Hence by decantation the clear water is poured into a clean separate container
Thus mud remain in the bottom and the mixture is separated
