What force is necessary to accelerate a 1050 kg car at a rate of 10 m/s2?

A flying squirrel has a mass of 0. 765 kg. He jumps off the tree and hits the ground with 125 joules of energy. Determine how hi

uranmaximum [27]

Answer:

Height, h = 16.67 m

Explanation:

We have,

Mass of a squirrel is 0.765 kg.

He jumps off the tree and hits the ground with 125 joules of energy.

It is required to find the height up on the tree the squirrel was when it jumped.

The energy possessed by the squirrel is called its gravitational potential energy. It can be given by :

$E=mgh$

h is height up on the tree the squirrel was when it jumped

$h=\dfrac{E}{mg}\\\\h=\dfrac{125\ J}{0.765\ kg\times 9.8\ m/s^2}\\\\h=16.67\ m$

So, the squirrel will go to a height of 16.67 m.

6 0

3 years ago

Mechanical energy often changes between potential and kinetic energy. True or False

Allushta [10]

I wanna say its ture but it didnt exactly say that is transfered from those types of energy so I would just say false

8 0

2 years ago

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a skydiver jumped out of a plane and fell 9 miles to the ground. his average speed while falling was 174 miles/hour. how much ti

shutvik [7]

Answer:

t = 0.051 seconds

Explanation:

Given that,

A skydiver jumped out of a plane and fell 9 miles to the ground. It means 9 miles is the distance covered.

The average speed of the skydiver is 174 miles/hour

We need to find the time for which he dive last. It means t is the time taken. Total distance covered divided by time taken is called average speed. So,

$v=\dfrac{d}{t}\\\\t=\dfrac{d}{v}\\\\t=\dfrac{9}{174}\\\\t=0.051\ s$

So, a skydiver dive for 0.051 seconds.

6 0

2 years ago

for the primitive yo-yo in fig, to find the downward acceleration of the cylinder and the tension in the string. you can take th

mixas84 [53]

The downward acceleration of the solid cylinder at the given tension in the string is determined as 2Tr/MR.

<h3>Downward acceleration of the cylinder</h3>

The downward acceleration of the solid cylinder is determined from the principle of conservation of angular momentum as shown below;

Iα = Tr

where;

I is moment of inertia of the solid cylinder
α is angular acceleration of the cylinder
T is tension in the string
r is length of the string

α = Tr/I

$\frac{a}{R} = \frac{Tr}{I} \\\\\frac{a}{R} = \frac{Tr}{\frac{1}{2} MR^2}\\\\\frac{a}{R} =\frac{2Tr}{MR^2} \\\\a = \frac{2Tr}{MR}$

where;

a is the downward acceleration of the solid cylinder
R is radius of the cylinder

Thus, the downward acceleration of the solid cylinder at the given tension in the string is determined as 2Tr/MR.

Learn more about acceleration here: brainly.com/question/605631

#SPJ1

7 0

1 year ago

Definition of Newton’s first law of motion

kipiarov [429]

Newton's first law of motion - sometimes referred to as the law of inertia. Newton's first law of motion is often stated as. An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

3 0

3 years ago

Read 2 more answers