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3 years ago

The rate of doing work is called?

Physics

2 answers:

Lorico [155]3 years ago

8 0

The rate of doing work is called power

Hope I helped
jcossin22

iragen [17]3 years ago

7 0

- - The rate, according to physics, of doing work, is called "power"

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How many joules of heat are needed to raise the temperature of 50.0 g of aluminum from 10°C to 110°C, if the specific heat of al

dusya [7]

Answer:

Heat required to raise the temperature of the aluminium is 4750 J

Explanation:

As we know that the heat energy required to raise the temperature of the aluminium is given as

$Q = ms\Delta T$

here we know that

m = 50 g

$\Delta T = 110 - 10$

$\Delta T = 100 ^oC$

so we have

$Q = 50(0.95)(100)$

$Q = 4750 J$

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4 years ago

The most common listening problem is

djverab [1.8K]

I think the correct answer is C

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3 years ago

The radiation detector that uses detection of flashes of light is a _____

Maslowich

The radiation detector that uses detection of flashes of light is a <u>scintillation counter.</u>

<h3>What is a scintillation counter?</h3>

A scintillation counter detects and measures ionizing radiation by using the excitation action of incoming radiation on a scintillating substance and detecting the light pulses that arise.

One of the most critical considerations for anyone who operate with or near radiation is being aware of the amounts of radiation present.

This is generally performed through the use of several types of radiation detectors.

The radiation detector that uses detection of flashes of light is a scintillation counter.

Hence,scintillation counter is the correct answer.

To learn more about the scintillation counter, refer:

brainly.com/question/12763694

#SPJ4

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2 years ago

Which of the following determines the range of spectral lines produced during electron transition?. . A.The total number of ener

KengaRu [80]

Answer: A.The total number of energy levels the electron can jump to.

Explanation:

Spectral lines are bright or dark lines over continuous spectrum which occur due to emission or absorption of energy.

When an electron jumps to or from one energy level to another energy level, spectral lines are produced. The range of spectral lines depends on the number of energy levels available to which the electron can jump. This depends the amount of energy gained/lost by the electron.

Thus, the correct answer is: A.The total number of energy levels the electron can jump to.

8 0

3 years ago

From a window 20 feet above the ground, the angle of elevation to the top of a building across the street is 78°, and the angle

Papessa [141]

The answer would be 371.16 ft.

Refer to the diagram for the scenario. The drawing is not to scale.

Notice the diagram that you will find to adjacent right triangles. All you need to do is first solve for the needed side of one triangle, by using one side.

It sounds confusing I know, but let's do this step by step.

Angle of depression is 15°.

We use this first because we do not have enough data to use the angle of elevation.

To get the adjacent side, we use the trigonometric function TOA which means:

$tan\theta= \dfrac{opposite}{adjacent}$

We use the height of the first building as our reference, so our given will be:

Opposite = 20ft

θ = 15°

Now we put that into our formula:

$tan\theta= \dfrac{opposite}{adjacent}$

$Tan15 = \dfrac{20ft}{adjacent}$

$adjacent = \dfrac{20ft}{Tan15}$

Adjacent = 74.64 ft

Angle of elevation is 78°:

Now that we have that we can solve for the height from the point of 20ft. We use the same formula, because we are looking for the opposite, given the adjacent.

$tan\theta= \dfrac{opposite}{adjacent}$

$Tan78 = \dfrac{opposite}{74.64ft}$

$(74.64ft)(Tan78) = opposite$

351.16ft = Opposite

Now that's the height from the top of the first building. To get the total height of the building we just add the 20ft.

351.16ft + 20 ft = 371.16ft

<em>The building across the street is 371.16 ft tall.</em>

5 0

3 years ago