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3 years ago

Identify an environmental condition in the ecosystem above and how it can affect the ecosystem

1 answer:

4 0

Deforestation- there are no more homes for some animals and insects after a forest is cut down.

desertification- when deserts get larger it destroys other ecosystems.

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Describe how to test your unknown salt mixture for the presence of<br>Na3PO4.12H2O.

klemol [59]

Na3PO4*12H2O + BaCl2*2H2O = Ba3(PO4)2 + NaCl + H2O

add barium chloride to your Na3PO4.12H2O a white precipitate of Ba3(PO4)2 will be formed wrt salt(NaCl) and water(H20) if Na3PO4.12H2O. will be there.

6 0

3 years ago

A 15.0 L tank of gas is contained at a high pressure of 8.20 x 10^4 torr. The tank is opened and the gas expands into an empty c

Inga [223]

Answer:

20.5torr

Explanation:

Given parameters:

V₁ = 15L

P₁ = 8.2 x 10⁴torr

V₂ = 6 x 10⁴L

Unknown:

P₂ = ?

Solution:

To solve this problem we have to apply the claims of Boyle's law.

Boyle's law is given mathematically as;

P₁ V₁ = P₂V₂

where P₁ is the initial pressure

V₁ is the initial volume

P₂ is final pressure

V₂ is final volume

8.2 x 10⁴ x 15 = P₂ x 6 x 10⁴

P₂ = 20.5torr

5 0

3 years ago

What are the moles of silver metal produced from 0.0999 mol of copper?

julia-pushkina [17]

Answer:

1234567i9812345678912121212121

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3 years ago

Please following me in the branily app ~♥~

Bas_tet [7]

Answer:

$\huge\colorbox{pink}{✏﹏ \: BlackPink\: }$

Omg!!!!! BlackPink!!!!!

# Blinkeu~~ ♡

8 0

3 years ago

Read 2 more answers

Consider the reaction at 25 °C. H2O(l) ↔ H2O(g) ΔG° = 8.6 kJ/mol Calculate the pressure of water at 25 °C (Hint: Get K eq)

tangare [24]

Answer:

$\boxed{\text{23.4 mmHg}}$

Explanation:

H₂O(ℓ) ⟶ H₂O(g)

$K_{\text{p}} = p_{\text{H2O}}$

$\text{The relationship between $\Delta G^{\circ}$ and $K_{\text{ p}}$ is}\\\Delta G^{\circ} = -RT \ln K_{\text{p}}$

Data:

T = 25 °C

ΔG° = 8.6 kJ·mol⁻¹

Calculations:

T = (25 + 273.15) K = 298.15 K

$\begin{array}{rcl}8600 & = & -8.314 \times 298.15 \ln K \\8600 & = & -2478.8 \ln K\\-3.47 & = & \ln K\\K&=&e^{-3.47}\\& = & 0.0311\end{array}$

Standard pressure is 1 bar.

$p_{\text{H2O}} = \text{0.0311 bar} \times \dfrac{\text{750.1 mmHg}}{\text{1 bar}} = \textbf{23.4 mmHg}\\\\\text{The vapour pressure of water at $25 ^{\circ}\text{C}$ is $\boxed{\textbf{23.4 mmHg}}$}$

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3 years ago