Consider this equilibrium: I2(s) + H2O(l) H + (aq) + I-(aq) + HOI(aq). What is the Keq expression for this equilibrium?

1 answer:

3 0

<span>The Keq expression for I2(s) + H2O(l) H + (aq) + I-(aq) + HOI(aq) equilibrium is H2(g) + I2(g) <----> 2 HI(g).In this Keq expression hydrogen reacts with iodine gives Hydrogen Iodide.HI is a diatomic molecule and it is one of the primary source of iodine which act as a reducing agent.Totally it is the reverse chemical equilibrium reaction.</span>

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