Answer:
The volume of HCl to be added to completely react with the ammonia is 0.032 L or 32mL
Explanation:
Using the formula
Ca Va = Cb Vb
Cb = 0.32 M
Vb = 50 mL = 50/1000 = 0.050L
Ca = 0.5 M
Va =?
Substituting for Va in the equation, we obtain:
Va = Cb Vb / Ca
Va = 0.32 * 0.05 / 0.5
Va = 0.016 / 0.5
Va = 0.032 L
The volume of HCl to be added to completely react with the ammonia is 0.032 L or 32mL
Answer:
<em>Alkali metals are among the most reactive metals. This is due in <u>part to their larger atomic radii and low ionization energies.</u> They tend to donate their electrons in reactions and have an oxidation state of +1. ... All these characteristics can be attributed to these elements' large atomic radii and weak metallic bonding.</em>
Explanation:
<em>I </em><em>hope</em><em> it</em><em> will</em><em> help</em><em> you</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>
<em>#</em><em>C</em><em>A</em><em>R</em><em>R</em><em>Y</em><em>O</em><em>N</em><em>L</em><em>E</em><em>R</em><em>A</em><em>N</em><em>I</em><em>N</em><em>G</em>
Answer:
propane -1 2 3 - trioic acid
Answer:
The answer to your question is 8.74 g of He
Explanation:
Data
V = 2.4 x 10² L
P = 99 kPa
T = 0°C
mass = ?
Process
1.- Convert kPa to atm
P = 99 kPa = 99000 Pa
1 atm --------------- 101325 Pa
x --------------- 99000 Pa
x = (99000 x 1) / 101325
x = 0.977 atm
2.- Convert temperature to °K
°K = 273 + 0
°K = 273
3.- Substitution
PV = nRT
- Solve for n
n = PV / RT
n = (0.977)(2.4 x 10²) / (0.082)(273)
n = 24.48 / 22.386
n = 1.093 moles
4.- Calculate the grams of He
8 g -------------------- 1 mol
x -------------------- 1.093 moles
x = (1.093 x 8) / 1
x = 8.74 g
The potassium will donate one of its valence electrons
