Answer:
Metal A will heat up faster
Explanation:
Step 1: Data given
Mass of the 2 metals = 1.00 grams
The specific heat of metal A is 0.568j/g* °c
The specific heat of metal B is 1.34j/g*°c
Initial temperature = 80 °C
Step 2: Calculate energy needed
A high specific heat value means that it takes MORE energy to raise (or lower) its temperature.
A low value means that it does not take very much energy to heat or cool it.
Step 3: Calculate energy needed to raise 1 °C
Q = m*c*ΔT
Metal A: Q = 1.00g * 0.568 J/g°C * 1°C
Q = 0.568 J
Metal B Q = 1.00g * 1.34 J/g°C * 1°C
Q = 1.34 J
We need 0.568 Joules energy to raise the temperature with 1°C for metal A.
We need 1.34 Joules energy to raise the temperature with 1°C for metal B.
Since we need less energy to raise the temperature for metal A, it will heat up faster.
Answer:
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Answer:
12.0
Explanation:
i know because i did this in 10th grad
Answer:
Selenium
Explanation:
Oxygen is present in the group sixteen.
This group consist of oxygen, sulfur, selenium, tellurium and polonium.
All of these have same number of valance electrons thus they show similar properties.
From the given list of elements only selenium is belong to oxygen family thus it has properties similar to the oxygen.
Electronic configuration of oxygen:
O = [He] 2s² 2p⁴
Electronic configuration of selenium:
Se = [Ar] 3d¹⁰ 4s² 4p⁴
While aluminium, boron and phosphorus are belongs to other groups that's why their properties are not similar to the phosphorus.
phosphorus is present in group 15.
Boron and aluminium are present in group 13.