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jekas [21]
2 years ago
11

What happens in the body when we break down carbohydrates? Explain the whole course of events.

Chemistry
1 answer:
JulsSmile [24]2 years ago
8 0

Answer:

Energetic molecules are formed, or rather the energetic currency to be able to live, which we call ATP.

Explanation:

ATP is a molecule that arises from the degradation of carbohydrates, these are destroyed for the first time in the mouth by the enzyme salivary amylase, then by the stomach, and finally they are absorbed in the intestine in the form of glucose, this glucose enters the bloodstream, entering the cells through insulin.

Once glucose is entered into the cell, it completes an energetic cycle, called the krebs cycle, which provides 36 to 38 ATP.

Atp, is adenosine tri phosphate, phosphate bonds protect a lot of energy, this is how the body generates the following reaction when it needs energy, releasing energy to the environment to be able to produce from locomotion to respiration:

ATP -----> ADP + Pi

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What is the mole fraction of O2O2 in a mixture of 15.1 gg of O2O2, 8.19 gg of N2N2, and 2.46 gg of H2H2
SVETLANKA909090 [29]

Answer:

Mole fraction O₂=  0.43

Explanation:

Mole fraction is the moles of gas/ total moles.

Let's determine the moles of each:

Moles O₂ → 15.1 g / 16 g/mol = 0.94

Moles N₂  →  8.19 g / 14 g/mol = 0.013

Moles H₂  → 2.46 / 2 g/mol = 1.23

Total moles = 2.183

Mole fraction O₂= 0.94 / 2.183 → 0.43

3 0
3 years ago
Coca cola is similar to tomato juice because
olya-2409 [2.1K]
B.) Because they both are Acids

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4 0
3 years ago
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During beta-oxidation of fatty acids, ___________ is produced in peroxisomes but not in mitochondria. A) acetyl-CoA B) FADH 2 C)
stepan [7]

Answer:

The correct option is D

Explanation:

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3 years ago
he heat of fusion of tetrahydrofuran is . Calculate the change in entropy when of tetrahydrofuran melts at . Be sure your answer
lana [24]

Answer:

\Delta S=1.8x10^{-3}\frac{kJ}{K}=1.8\frac{J}{K}

Explanation:

Hello.

In this case, given the heat of fusion of THF to be 8.5 kJ/mol and freezing at -108.5 °C, for the required mass of 5.9 g, we can compute the entropy as:

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Whereas n accounts for the moles which are computed below:

n=5.9g*\frac{1mol}{72g} =0.082mol

Thus, the entropy turns out:

\Delta S=\frac{0.0819mol*8.5 kJ/mol}{(-108.5+273.15)K}\\\\\Delta S=1.8x10^{-3}\frac{kJ}{K}=1.8\frac{J}{K}

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3 0
3 years ago
What is the ozone hole and how does it affect humans?
denis-greek [22]

Answer:

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