Answer:
AsF3:C2CI6
4:3
1.3618 moles: 1.02135 moles(1.3618÷4×3)
C2CI6 is the limting reagent
So the number of moles for AsCI3 is 0.817 moles( number of moles of the limting reagant) ÷3 ×4 (according to ratio by balancing chemical equation)=1.09 moles(3 s.f.)
or
Balanced equation
4AsF3 + 3C2Cl6 → 4AsCl3 + 3C2Cl2F4
Use stoichiometry to calculate the moles of AsCl3 that can be produced by each reactant.
Multiply the moles of each reactant by the mole ratio between it and AsCl3 in the balanced equation, so that the moles of the reactant cancel, leaving moles of AsCl3.
Explanation:
Here try this presentation, it should help :)
https://prezi.com/6ofdo3fadl9a/exothermic-and-endothermic-reactions-in-everyday-life/
Diffusion is the net movement of particles from a hight concentration to a low one
Explanation:
To round to a significant figure:
- look at the first non-zero digit if rounding to one significant figure
- look at the digit after the first non-zero digit if rounding to two significant figures
- draw a vertical line after the place value digit that is required
- look at the next digit
- if it's 5 or more, increase the previous digit by one
- if it's 4 or less, keep the previous digit the same
- fill any spaces to the right of the line with zeros, stopping at the decimal point if there is one
<h3>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em></h3>
Answer:
9.17 g
Explanation:
1) Calculate mols of PCl5
PCl5 (aq) + 4H2O (l) ⟶ H3PO4 (aq) + 5HCl (aq)
Mass of PCl5: 26.5g
Molar Mass of PCl5 208.24g/mol
Mol of PCl5 = Mass PCl5 /Molar mass PCl5 = 26.5g / (208.24g/mol) = 0.127257011 mol
2) Calculate mols of water needed to react
Mols of H2O per 1 Mols of PCl5 = 4 (because 4 water is needed to Phosphorus pentachloride).
Mols of H2O = Mol of PCl5 * 4 = 0.127257011 * 4 = 0.509028044 mols
3) Calculate Grams of water needed to react
Mols of H2O = 0.509028044 mols
Molar Mass of H2O = 18.015 g/mol
Mass of H2O = Mols of H2O * Molar Mass of H2O
= 0.509028044 mols* 18.015 g/mol = 9.17014021 g
sf = 3
9.17 g