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3 years ago

How many atoms are there in 5.699 g of cobalt, Co? Express your answer with the appropriate significant figures and unit.

1 answer:

6 0

5.824x10^22 atoms of cobalt are in 5.699 grams of cobalt. First, determine the number of moles of cobalt you have by dividing the mass of cobalt by the atomic weight of cobalt. So Atomic weight cobalt = 58.933195 Mole cobalt = 5.699 g / 58.933195 g/mol = 0.096702716 mol Now to determine the number of atoms, multiply by Avogadro's number. So 0.096702716 * 6.0221409x10^23 = 5.823574x10^22 Rounding to 4 significant figures, gives 5.824x10^22

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Hydrogen peroxide (H2O2) readily decomposes to form water and oxygen gas: 2H2O2(aq) → 2H2O(l) + O2(g) What concentration of hydr

Anastaziya [24]

Hydrogen peroxide is a powerful oxidizer. When exposed to sunlight it quickly decomposes to form water and oxygen as given by the following equation.

2H2O2(aq) → 2H2O(l) + O2(g)

Hydrogen peroxide is commercially available as a 30% w/w solution, which is the concentration that would facilitate the above reaction. This implies that the concentration would be 30 g of H2O2 in 100 g of the solution.

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3 years ago

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2 years ago

A nitrde ion has 7protons,8nutrons and 10 electrons. what is the overall change

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2 years ago

Given that Δ H ∘ f [ Br ( g ) ] = 111.9 kJ ⋅ mol − 1 Δ H ∘ f [ C ( g ) ] = 716.7 kJ ⋅ mol − 1 Δ H ∘ f [ CBr 4 ( g ) ] = 29.4 kJ

JulsSmile [24]

Answer:

283.725 kJ ⋅ mol − 1

Explanation:

C(s) + 2Br2(g) ⇒ CBr4(g) , Δ H ∘ = 29.4 kJ ⋅ mol − 1

$\frac{1}{2}$ Br2(g) ⇒ Br(g) , Δ H ∘ = 111.9 kJ ⋅ mol − 1

C(s) ⇒ C(g) , Δ H ∘ = 716.7 kJ ⋅ mol − 1

4*eqn(2) + eqn(3) ⇒ 2Br2(g) + C(s) ⇒ 4 Br(g) + C(g) , Δ H ∘ = 1164.3 kJ ⋅ mol − 1

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so,

average bond enthalpy is $\frac{1134.9}{4}$ = 283.725 kJ ⋅ mol − 1

4 0

3 years ago

4. How many milligrams are in 5.25 x 10-13 kg? the “-13” is an exponent

rusak2 [61]

5. 25 x 10⁻⁷mg

Explanation:

This is mass conversion from mg to kg;

The kg is a quantity of mass used to measure the amount of matter in a substance.

Given mass = 5.25 x 10⁻¹³kg

The kilo- is a prefix that denotes 10³

therefore;

1000g = 1kilogram

the milli- is a prefix that denotes 10⁻⁻³

1000mg = 1g

Now that we know this, we can convert:

5.25 x 10⁻¹³kg x $\frac{1000g}{1kg} x \frac{1000mg}{1g}$ = 5. 25 x 10⁻¹³ x 10⁶mg

= 5. 25 x 10⁻⁷mg

learn more:

Conversion brainly.com/question/1548911

#learnwithBrainly

8 0

3 years ago