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3 years ago

How many atoms are there in 5.699 g of cobalt, Co? Express your answer with the appropriate significant figures and unit.

1 answer:

6 0

<span>5.824x10^22 atoms of cobalt are in 5.699 grams of cobalt. First, determine the number of moles of cobalt you have by dividing the mass of cobalt by the atomic weight of cobalt. So Atomic weight cobalt = 58.933195 Mole cobalt = 5.699 g / 58.933195 g/mol = 0.096702716 mol Now to determine the number of atoms, multiply by Avogadro's number. So 0.096702716 * 6.0221409x10^23 = 5.823574x10^22 Rounding to 4 significant figures, gives 5.824x10^22</span>

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Calculating the Molecular Weight and Subunit Organization of a Protein From Its Metal Content The element molybdenum (atomic wei

Deffense [45]

Answer:

Dimer of two peptide chains with 1 mole of molybdenum metal each.

Explanation:

Percentage of molybdenum in protein = 0.08%

Molecular mass of nitrate reductase = 240,000 g

Mass of molybdenum = x

$0.08\%=\frac{x}{240,000 g}\times 100=192 g$

Moles of molybdenum = $\frac{192 g}{95.95 g/mol}=2.00 mol$

Each peptide chain of nitrate reductase contain 1 mole of molybdenum.

This means that nitrate reductase is composed of to two peptide chains. And in each peptide there is a single mole of molybdenum metal.

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3 years ago

Explain why you can boil water in a pot without the pot also boiling

ddd [48]

Because the pot isn’t water it just gets really hot and you can burn yourself if you touch it

3 0

3 years ago

Which of the following will have a larger radius than zinc ? Gallium (Ga) Magnesium (Mg) Aluminum (Al) Strontium (St)

oksian1 [2.3K]

Answer:

Strontium (St)

Explanation:

The atom that will have a larger radius than zinc is strontium, Sr.

Atomic radius is defined as the half of the inter-nuclear distance between two covalently bonded atoms of non-metallic elements or half of the distance between two nuclei in the solid state of metals.

Across the period atomic radii decreases progressively due to the increase in nuclear charge.
Down a group atomic radii increase progressively due to the successive shells of electrons being added.
Since strontium satisfies the criteria, it has the larger atomic radius.

7 0

3 years ago

The density of cadmium is 8.65 g/mL, what is the volume of a 33.4 g object made of pure cadmium?

Rzqust [24]

Answer:

Volume = 3.86 ml (Approx)

Explanation:

Given:

Density of cadmium = 8.65 g/ml

Mass of pure object = 33.4 g

Find:

Volume pure cadmium

Computation:

Volume = Mass / Density

Volume = 33.4 / 8.65

Volume = 3.86 ml (Approx)

6 0

3 years ago

5.943x10^24 molecules of H3PO4 will need how many grams of Mg(OH)2 in the reaction below? 3 Mg(OH)2 + 2 H3PO4 -------> 1 Mg3(

professor190 [17]

Answer:

Mass of Mg(OH)₂ required for the reaction = 863.13 g

Explanation:

3Mg(OH)₂ + 2H₃PO₄ -------> Mg₃(PO₄)₂ + 6H₂O

(5.943 x 10²⁴) molecules of H₃PO₄ is available fore reaction. Mass of Mg(OH)₂ required for reaction.

According to Avogadro's theory, 1 mole of all substances contain (6.022 × 10²³) molecules.

This can allow us find the number of moles that (5.943 x 10²⁴) molecules of H₃PO₄ represents.

1 mole = (6.022 × 10²³) molecules.

x mole = (5.943 x 10²⁴) molecules

x = (5.943 x 10²⁴) ÷ (6.022 × 10²³)

x = 9.87 moles

From the stoichiometric balance of the reaction,

2 moles of H₃PO₄ reacts with 3 moles of Mg(OH)₂

9.87 moles of H₃PO₄ will react with y moles of Mg(OH)₂

y = (3×9.87)/2 = 14.80 moles

So, 14.8 moles of Mg(OH)₂ is required for this reaction. We them convert this to mass

Mass = (number of moles) × Molar mass

Molar mass of Mg(OH)₂ = 58.3197 g/mol

Mass of Mg(OH)₂ required for the reaction

= 14.8 × 58.3197 = 863.13 g

Hope this Helps!!!

5 0

3 years ago

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