How many Grams of NO is produced if 12g of O2 is combined with excess ammonia?
1 answer:
Answer:
9g
Explanation:
moles O2 = mass / Mr = 12 / 2(16.0) = 0.375
ratio O2 : NO = 5:4
moles NO produced = 0.375 * 4/5 = 0.3
mass NO = Mr * mol = (14.0+16.0) * 0.3 = 9g
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