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Usimov [2.4K]
3 years ago
7

____H2 + ____O2 ---> ____H20 2, 1, 1 2, 2, 1 2, 1, 2 1, 2, 2

Chemistry
2 answers:
marin [14]3 years ago
8 0

Answer:

2 H2 + O2 => 2 H2O aka 2, 1, 2

Explanation:

H2 + O2 => H2O

On the left side there are currently 2 H's and 2 O's

On the right side there are currently 2 H's and 1 O

We have to match both sides to equal the same number of H's and O's

As previously stated, both sides have 2 H's without doing anything to them so let's ignore that and skip to the O2

One the left there are 2 O's and on the right there is 1 O

We cannot remove O's so in order to equal each other we must look at the right side

To get from 1 O to 2 O, we can multiply H2O by 2

This will give us 4 H's, and 2 O's

This makes the O's equivalent to each other

But now, the H's are imbalanced

The left side has 2 H's while the right side has 4 H's

To make the 2 H's go to 4 H's, we multiply the 2 H's by 2

This gives us 4 H's on both sides and now the equation is balanced

Tems11 [23]3 years ago
6 0
2H2+O2----->2H2O. I hope this helps
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Answer:

trigonal planar

Explanation:

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Elemental exonium (not a real element) consists of two major isotopes abundance mass 18% 98 amu 82% 112 amu what is the atomic w
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3 0
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Five students performed a Kjeldahl nitrogen analysis of a protein sample. The following weight % nitrogen values were determined
Sunny_sXe [5.5K]

Answer:

G_calculated = 1.756

The outlier should be rejected, as G_cal > G_tab (= 1.463) at 95 % confidence.

Explanation:

The Grubb's test is used for identifying an outlier in data, which is from the same population. For this, a statistical term, G, is calculated for the suspected outlier. If the calculated value is greater than the tabulated G value then the suspected value is rejected. This term is given as,

G_calculated = | suspect value - mean| / s

Here,  suspect value is 13.8, mean is to be taken of all the data (including suspected value). s is the standard deviation of the sample data.

s is calculated from the following formula:

s = (Σ(xi - x)²/(N-1))^1/2

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From the above formula, s is found to be

Standard Deviation, s = 0.820

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G_calculated = | 13.8 - 15.24| / (0.820)

G_ calculated = 1.756

The tabulated G value at 95 % confidence and N -1 (5 - 1 = 4) degree of freedom is, 1.463.

As calculated G (1.756) is greater than the tabulated G (1.463), the value 13.8 is considered an outlier at 95 % confidence.  

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