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3 years ago

H2 + O2 ---> H20 2, 1, 1 2, 2, 1 2, 1, 2 1, 2, 2

Chemistry

2 answers:

marin [14]3 years ago

8 0

Answer:

2 H2 + O2 => 2 H2O aka 2, 1, 2

Explanation:

H2 + O2 => H2O

On the left side there are currently 2 H's and 2 O's

On the right side there are currently 2 H's and 1 O

We have to match both sides to equal the same number of H's and O's

As previously stated, both sides have 2 H's without doing anything to them so let's ignore that and skip to the O2

One the left there are 2 O's and on the right there is 1 O

We cannot remove O's so in order to equal each other we must look at the right side

To get from 1 O to 2 O, we can multiply H2O by 2

This will give us 4 H's, and 2 O's

This makes the O's equivalent to each other

But now, the H's are imbalanced

The left side has 2 H's while the right side has 4 H's

To make the 2 H's go to 4 H's, we multiply the 2 H's by 2

This gives us 4 H's on both sides and now the equation is balanced

Tems11 [23]3 years ago

6 0

2H2+O2----->2H2O. I hope this helps

You might be interested in

Please help balance _Ch7H16+_O2=_CO2+_H2O

iren2701 [21]

Answer:

C7H16 + 11 O2 → 7 CO2 + 8 H2O

This is an oxidation-reduction (redox) reaction:

7 C-16/7 - 44 e- → 7 CIV (oxidation)

22 O0 + 44 e- → 22 O-II (reduction)

C7H16 is a reducing agent, O2 is an oxidizing agent.

Reactants:

C7H16

Names: Dioxygen source: wikidata, accessed: 2019-09-07, Oxygen source: ICSC, accessed: 2019-09-04source: wikidata, accessed: 2019-09-07, Oxygen (liquefied) source: ICSC, accessed: 2019-09-04

Appearance: Odourless compressed gas source: ICSC, accessed: 2019-09-04; Liquefied gas. colourless-to-blue extremely cold liquid source: ICSC, accessed: 2019-09-04

Products:

CO2

Names: Carbon dioxide source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04source: NIOSH NPG, accessed: 2019-09-02, {{plainlist| source: wikipedia, accessed: 2019-09-27, CO2 source: wikidata, accessed: 2019-09-02

Appearance: Colorless gas source: wikipedia, accessed: 2019-09-27; Odourless colourless compressed liquefied gas source: ICSC, accessed: 2019-09-04; Colorless, odorless gas. [Note: Shipped as a liquefied compressed gas. Solid form is utilized as dry ice.] source: NIOSH NPG, accessed: 2019-09-02

H2O – Water, oxidane source: wikipedia, accessed: 2019-09-27

Other names: Water (H2O) source: wikipedia, accessed: 2019-09-27, Hydrogen hydroxide (HH or HOH) source: wikipedia, accessed: 2019-09-27, Hydrogen oxide source: wikipedia, accessed: 2019-09-27

Appearance: White crystalline solid, almost colorless liquid with a hint of blue, colorless gas source: wikipedia, accessed: 2019-09-27

Search by reactants (C7H16, O2)

1 O2 + C7H16 → H2O + CO2

2 O2 + C7H16 → H2O + CO

3 O2 + C7H16 → H2O + CO2 + CO

4 O2 + C7H16 → H2 + CO2

Search by products (CO2, H2O)

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1 HCl + CaCO3 → H2O + CO2 + CaCl2

2 HCl + NaHCO3 → H2O + CO2 + NaCl

3 O2 + CH4 → H2O + CO2

4 NaHCO3 → H2O + CO2 + Na2CO3

5 H2SO4 + KMnO4 + (COOH)2 → H2O + CO2 + K2SO4 + MnSO4

6 O2 + C3H8 → H2O + CO2

7 H2SO4 + K2CO3 → H2O + CO2 + K2SO4

8 O2 + C2H6 → H2O + CO2

9 CH3COOH + NaHCO3 → H2O + CO2 + CH3COONa

10 HCl + Na2CO3 → H2O + CO2 + NaCl

12345678910...

Search by reactants (C7H16, O2) and by products (CO2, H2O)

1 O2 + C7H16 → H2O + CO2

2 O2 + C7H16 → H2O + CO2 + CO

Explanation:

8 0

2 years ago

I will give brainliest. If you burn the carbon in limited air, the reaction is

Fynjy0 [20]

This reaction is different in that the carbon undergoes an incomplete combustion as opposed to complete combustion where carbon is fully oxidized. A caveat: incomplete combustion products in general can be difficult to predict without sufficient information, as it's not uncommon to obtain a mixture of different products.

Here, we are told that solid carbon is burned in limited air to produce a gas. I am presuming that, in the equation that's given, the "0" represents a blank where you must fill in a chemical symbol. In this case, our equation would be: 2C(s) + O₂(g) → 2CO(g).

There is not enough information here to provide the numerical answers to the two questions. From the words in the question (e.g., "is different" and "this time"), it would seem that this question is an excerpt from a larger or preceding question where specific numbers had been provided or computed.

However, it's possible to make some general observations on how one may go about answering these questions if one had more information.

Since we're to assume that oxygen is the limiting reagent, if one is given the amount of solid carbon (either in mass, moles, or number of atoms), it's possible to determine the moles of CO(g) that's produced since C and CO have an equal stoichiometric ratio. So, for example, if one burns 2 moles of C(s), then 2 moles of CO(g) would be produced.

But, there is still not enough information to compute the volume of CO gas if this is the line of questioning. We don't know, for instance, the temperature or pressure of the reaction conditions. In fact, the only way it would be possible to answer this would be if you were given beforehand a conversion factor that relates the volume of CO(g) to its quantity (e.g., to assume that one mole of gas occupies x liters).

As for the second question, this would depend on what you know about the quantity of the C(s) reacted and/or the quantity (or volume, from question a) of CO(g) produced. If you can get the number of moles of C(s) reacted or CO(g) produced, the number of moles of O₂(g) used up: It would be half the number of moles of C(s) reacted or half the number of moles of CO(g) produced). Again, it's impossible to determine the volume of O₂(g) using just the information provided here, so I suspect that you must have further information relating gas quantity to volume. As we did with CO(g), the volume of O₂(g) used up can be found using whatever conversion factor you have.

If you have any further information or questions, please feel free to follow up.

6 0

2 years ago

The songs of birds are part of a ritual to attractpotential partners of their own species. The song presents specific patterns r

liberstina [14]

Answer:

Explanation:

Bird courtship and mating dances include many unique ways to attract mates. Learn about their courtship behaviors and why they matter. ... When birders recognize courting birds, they can be sure to avoid disturbing ... the charming songs used to woo partners can help distinguish species so birds are sure ...

6 0

2 years ago

What information can be found on a diagram of the earths energy budget

Yanka [14]

Answer:

Explanation:

the balance between the energy that Earth receives from the Sun, and the energy the Earth radiates back into outer space after having been distributed throughout the five components of Earth's climate system.

6 0

3 years ago

The kingdom, protista, includes

lyudmila [28]

The kingdom, protista’s characteristics are that the organism (not a plant, animal or fungus) are: unicellular however some are multicellular like algae, are heterotrophic or autotrophic, others lives in water while some live in moist areas or human body, have a nucleus, cellular respiration is primarily aerobic, some are pathogenic (e.g. causing Malaria) and reproduction is mitosis or meiosis. This kingdom includes: Sacordinians – pseudopods (e.g. Amoeba, Foraminiferans.), Zooflagellates – flagellates (e.g. Trypanosoma gambiense), Ciliaphorans – ciliates (e.g. paramecium) and Sporozoans (e.g. Plasmodium).

3 0

3 years ago

Read 2 more answers

____H2 + ____O2 ---> ____H20 2, 1, 1 2, 2, 1 2, 1, 2 1, 2, 2

H2 + O2 ---> H20 2, 1, 1 2, 2, 1 2, 1, 2 1, 2, 2