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vodka [1.7K]
3 years ago
11

Help with question 4?

Mathematics
2 answers:
yarga [219]3 years ago
6 0
It is the last option. Since it is greater than or EQUAL TO, the circle is filled in. 
deff fn [24]3 years ago
5 0
I believe it is the last option, but pleae don’t come for me if you get it incorrect. But if that is the case, I apologize in advance for any inconveniences this may cause.

Kind regards!
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If the circumference of a circle is 12, and the angle measure of an arc is 60o, which is the length of the arc?
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gregori [183]

Step-by-step explanation:

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5 0
2 years ago
The volume of a spherical balloon is increasing at the rate of 25cm^3/min, how fast is the radius increasing when the radius is
S_A_V [24]

Answer:

So the radius is increasing at \frac{1}{64\pi} \frac{\text{cm}}{\text{min}}.

This is approximately 0.00497 cm/min that the radius is increasing.  

Step-by-step explanation:

V=\frac{4}{3}\pi r^3

The volume and radius are both things that are changing with respect to time.

So their derivatives will definitely not be 0.

Let's differentiate:

V'=\frac{4}{3} \pi \cdot 3r^2r'

I had to use constant multiple rule and chain rule.

We are given V'=+25 \frac{\text{cm^3}}{\text{min}} and r=20 \text{cm}.

We want to find r'.

Let's plug in first:

25=\frac{4}{3}\pi \cdot 3(20)^2r'

25=\frac{4}{3} \pi \cdot 3(400)r'

25=\frac{4}{3} \pi \cdot 1200r'

Multiply both sides by 3:

75=4 \pi \cdot 1200r'

75=4800 \pi r'

Divide both sides by 4800 \pi:

\frac{75}{4800 \pi}=r'

\frac{1}{64 \pi}=r'

So the radius is increasing at \frac{1}{64\pi} \frac{\text{cm}}{\text{min}}.

This is approximately 0.00497 cm/min that the radius is increasing.  

5 0
3 years ago
Read 2 more answers
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