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3 years ago

Plz help question below

Mathematics

1 answer:

zaharov [31]3 years ago

4 0

You just keep subtracting 3 yo the previous number, so day one would be $82 and day three would be $79...etc. Day five would be $70 so sweet

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solve this word problem leading to quadratic equation: the area of a rectangle is 60cm². The length is 11cm more than the width.

morpeh [17]

Answer:

Step-by-step explanation:

let : x The length and y the width you have this system :

xy =60....(1)

x = y+10...(2)

put the value for x in (1): (y+10)y =60

the quadratic equation is : y² +10y - 60 = 0

Δ =b² - 4ac a = 1 b= 10 c= - 60

Δ =10² - 4(1)(-60) = 324 =18²

y 1 = (-10-18)/2 negatif...... refused

y 2 = (-10+18)/2 =4

the width is 4

8 0

3 years ago

Make a table with the domain of {2,3,4,5,6} and draw a graph of the absolute value function y = 2|x-4| + 3.

Jet001 [13]

Answer:

<h2>In the attachment.</h2>

Step-by-step explanation:

$|a|=\left\{\begin{array}{ccc}a&for\ a\geq0\\-a&for\ a$

Put each value of x from the set {2, 3, 4, 5, 6}

to the equation y = 2|x - 4| + 3:

x = 2 → y = 2|2 - 4| + 3 = 2|-2| + 3 = 2(2) + 3 = 4 + 3 = 7 → (2, 7)

x = 3 → y = 2|3 - 4| + 3 = 2|-1| + 3 = 2(1) + 3 = 2 + 3 = 5 → (3, 5)

x = 4 → y = 2|4 - 4| + 3 = 2|0| + 3 = 2(0) + 3 = 0 + 3 = 3 → (4, 3)

x = 5 → y = 2|5 - 4| + 3 = 2|1| + 3 = 2(1) + 3 = 2 + 3 = 5 → (5, 5)

x = 6 → y = 2|6 - 4| + 3 = 2|2| + 3 = 2(2) + 3 = 4 + 3 = 7 → (6, 7)

Mark the points in the coordinates system.

The domain is only five numbers, therefore the graph of this function is only five points.

5 0

3 years ago

Read 2 more answers

Find the measures of the missing angles g, h, k, and m

Darina [25.2K]

Answer:

Angle g = 29 degrees

Angle h = 180-29 = 151 degrees

Angle k = 61 degrees

Angle m = 180 - 61 = 119 degrees

Step-by-step explanation:

6 0

3 years ago

For two events and , the probability that occurs is 0.8, the probability that occurs is 0.4, and the probability that both occur

sergey [27]

Answer:

P(B|A)=0.25 , P(A|B) =0.5

Step-by-step explanation:

The question provides the following data:

P(A)= 0.8

P(B)= 0.4

P(A∩B) = 0.2

Since the question does not mention which of the conditional probabilities need to be found out, I will show the working to calculate both of them.

To calculate the probability that event B will occur given that A has already occurred (P(B|A) is read as the probability of event B given A) can be calculated as:

P(B|A) = P(A∩B)/P(A)

= (0.2) / (0.8)

P(B|A)=0.25

To calculate the probability that event A will occur given that B has already occurred (P(A|B) is read as the probability of event A given B) can be calculated as:

P(A|B) = P(A∩B)/P(B)

= (0.2)/(0.4)

P(A|B) =0.5

7 0

4 years ago

Write the ratio as a fraction in simplest form. 32:42

maks197457 [2]

16/21 is your answer

You can take a 2 out of both numbers to get your answer

I hope this helped! :)

3 0

3 years ago

Read 2 more answers