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earnstyle [38]
3 years ago
12

Plz help question below

Mathematics
1 answer:
zaharov [31]3 years ago
4 0
You just keep subtracting 3 yo the previous number, so day one would be $82 and day three would be $79...etc. Day five would be $70 so sweet
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Which equation is rewritten in vertex form?
Zinaida [17]
(x + 3)^2 + (x + 4)^2 
= x^2 + 6x + 9 + x^2 + 8x + 16
= 2x^2 + 14x + 25
= 2(x^2 + 7x) + 25
= 2[(x + 7/2)^2  - 49/4] + 25
= 2(x + 7/2)^2 - 98/4 + 25
= 2(x + 7/2)^2 + 1/2


Its B

7 0
3 years ago
Find three consecutive integers whose sum is 51.
Julli [10]

Answer:

16,17,18

your welcome

7 0
3 years ago
2.5y=5 what is the answer to the equation?
postnew [5]

Answer:2

Step-by-step explanation:

2.5(2)

=5

7 0
3 years ago
Read 2 more answers
Can someone help with numbers 15 and 16
vichka [17]
15.

I had x before the movie.

x - 13.50 = 26.50

Add 13.50 to both sides of the equation:

x = 40

I had $40 before the movie.

16.

The original balance was x.

x - 161.15 = 423.28

Add 161.15 to both sides:

x = 584.43

The previous balance was $584.43
4 0
3 years ago
Find the first five terms of the recursive sequence <br> an=-6an-1 where a1=4.5
grandymaker [24]

Answer:

4.5, -27, 162,-972, 5832

Step-by-step explanation:

The given recursive definition is,

a_n=-6a_{n-1}, a_1=4.5

This will form a geometric sequence with first term 4.5 and common ratio r=-6.

When n=2, we have:

a_2=-6a_1 \\  \implies \: a_2=-6 \times 4.5 =  - 27

When n=3, we get:

a_3=-6a_2 \\  \implies \: a_3=-6 \times  - 27 =  162

When n=4, we get:

a_4=-6a_3 \\  \implies \: a_4=-6 \times 162 =  - 972

When n=5, we get:

a_5=-6a_4 \\  \implies \: a_5=-6 \times  - 972 = 5832

Therefore the first five terms are:

4.5, -27, 162,-972, 5832

3 0
3 years ago
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