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4 years ago

At what distance above Earth would a satellite have a period of 125 minutes

Physics

1 answer:

mash [69]4 years ago

5 0

Answer:

If a satellite orbiting the Earth has a period of 125 min, then it must be 1.90 x 106 m above the Earth's surface.

Explanation:

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A light-emitting diode (LED) connected to a 3.0 V power supply emits 440 nm blue light. The current in the LED is 11 mA , and th

zimovet [89]

Answer:

3.73 * 10^16 photons/sec

Explanation:

power supply = 3.0 V

Emits 440 nm blue light

current in LED = 11 mA

efficiency of LED = 51%

<u>Calculate the number of photons per second the LED will emit </u>

first step : calculate the energy of the Photon

E = hc / λ

=( 6.62 * 10^-34 * 3 * 10^8 ) / 440 * 10^-9

= 0.0451 * 10^-17 J

Number of Photon =( power supply * efficiency * current ) / energy of photon

= ( 3 * 0.51 * 11 * 10^-3 ) / 0.0451 * 10^-17

= 3.73 * 10^16 photons/sec

3 0

3 years ago

What is the key topic to consider when researching a potential employer

miss Akunina [59]

Answer:

check out the website

hope this helps

6 0

3 years ago

A 100 kg roller coaster car is located at the top of a hill where the height is 20 m. What is the velocity when it reaches the b

galina1969 [7]

The velocity of the car at the bottom of the hill=19.8 m/s

mass= 100 kg

height= h=20 m

Velocity at the bottom=V

Using the law of conservation of energy

potential energy at top = kinetic energy at the bottom

m g h= 1/2 m v²

g h= 1/2 v²

9.8 (20)=1/2 V²

V=19.8 m/s

Thus the velocity of car at the bottom of hill=19.8 m/s

4 0

3 years ago

Read 2 more answers

A centrifuge in a medical laboratory rotates at an angular speed of 3500 rev/min. When switched off, it rotates 46.0 times befor

BlackZzzverrR [31]

Answer:

The angular acceleration of the centrifuge is -231.74 rad/s².

Explanation:

Given that,

Angular speed = 3500 rev/min = 366 rad/s

We need to calculate the angular displacement

Using formula of angular displacement

$\theta=2\pi n$

Put the value into the formula

$\theta=2\pi\times46$

$\theta=289.02\ rad$

We need to calculate the angular acceleration

Using equation of motion

$\omega_{f}^2=\omega_{i}^2+2\alpha\theta$

$\alpha=\dfrac{\omega_{f}^2-\omega_{i}^2}{2\theta}$

$\alpha=\dfrac{0-(366)^2}{2\times289.02}$

$\alpha=-231.74\ rad/s^2$

Hence, The angular acceleration of the centrifuge is -231.74 rad/s².

3 0

3 years ago

A bar of silicon is 4 cm long with a circular cross section. If the resistance of the bar is 280 Ω at room temperature, what is

monitta

Answer:

r = 17.05 cm

Explanation:

Given that,

Length of silicon bar is 4 cm or 0.04 m

Resistance of the bar is 280 ohms

We know that the resistivity of the silicon is 640 Ωm

We need to find the cross-sectional radius of the bar. Let it is r.

Using definition of resistance of an object. It is given by :

$R=\rho\dfrac{l}{A}$

A is area of bar, A = πr²

So,

$R=\rho\dfrac{l}{\pi r^2}\\\\r^2=\dfrac{\rho l}{R\pi}\\\\r^2=\dfrac{640\times 0.04}{280\pi}\\\\r=0.1705\ m\\\\r=17.05\ cm$

So, the cross-sectional radius of the bar is 17.05 cm.

4 0

4 years ago