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san4es73 [151]
3 years ago
10

Which scenario would result in a decrease in population size, or a negative population growth?

Physics
2 answers:
Anestetic [448]3 years ago
5 0
I’m pretty sure the answer is b
Luba_88 [7]3 years ago
5 0

Answer:

The correct answer is option B.

Explanation:

Using Formula:

Population growth = (birth rate + immigration) – (death rate + emigration)

A) Birth rate = 14

Immigration = 14

Death rate = 14

Emigration = 0

Population growth = (14 + 14) – (14 + 0)= 14

B) Birth rate = 10

Immigration = 28

Death rate = 0

Emigration = 40

Population growth = (10 + 28) – (0 + 40)= -2

C) Birth rate = 17

Immigration = 0

Death rate = 5

Emigration = 12

Population growth = (17 + 0) – (5 + 12)= 0

D) Birth rate = 25

Immigration = 0

Death rate = 4

Emigration = 19

Population growth = (25 + 0) – (4 + 19)= 2

Scenario (B) would result in a decrease in population size, or a negative population growth.

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How far will a free falling object fall in 8.7 secs if it started from rest? Remember acceleration is negative for free fall. Do
sleet_krkn [62]

Answer:

h~=371.26m

Explanation:

when an object falls we use the equations of accelerated motion. There is only one that gives distance.

x = ut +  \frac{1}{2} a {t}^{2}

Since we have no initial velocity (started from rest) we can get rid of the (ut) term

where a we substitute g (gravitational acceleration, constant for given heights and almost 9.81m/s^2).

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4 0
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An amusement park ride consists of a rotating circular platform 11.1 m in diameter from which 10 kg seats are suspended at the e
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To solve this problem we will use the relationship given between the centripetal Force and the Force caused by the weight, with respect to the horizontal and vertical components of the total tension given.

The tension in the vertical plane will be equivalent to the centripetal force therefore

Tsin\theta= \frac{mv^2}{r}

Here,

m = mass

v = Velocity

r = Radius

The tension in the horizontal plane will be subject to the action of the weight, therefore

Tcos\theta = mg

Matching both expressions with respect to the tension we will have to

T = \frac{\frac{mv^2}{r}}{sin\theta}

T = \frac{mg}{cos\theta}

Then we have that,

\frac{\frac{mv^2}{r}}{sin\theta} =  \frac{mg}{cos\theta}

\frac{mv^2}{r} = mg tan\theta

Rearranging to find the velocity we have that

v = \sqrt{grTan\theta}

The value of the angle is 14.5°, the acceleration  (g) is 9.8m/s^2 and the radius is

r = \frac{\text{diameter of rotational circular platform}}{2} + \text{length of chains}

r = \frac{11.1}{2}+2.41

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Replacing we have that

v = \sqrt{(9.8)(7.96)tan(14.5\°)}

v = 4.492m/s

Therefore the speed of each seat is 4.492m/s

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