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ArbitrLikvidat [17]
3 years ago
15

Which types of orbitals are found in the principal energy level n = 2?

Chemistry
2 answers:
uranmaximum [27]3 years ago
5 0

Answer:

option d

Explanation:

plato users

AfilCa [17]3 years ago
3 0
Remember this:

1) n is principal quantum number and represents the energy level.

2) l is the second quantum number and represent the type of orbital.

3) l can take values from 0 to n - 1

4) each number of l is associated with a type of orbital.  This table shows the equivalence:
 
l number       type of orbital

0                    s

1                    p

2                    d

3                     f

With that, you can tell that n = 2 permits l = 0 and 1, which is orbitals s and p.

Therefore, the answer is the option D) s, p.
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adoni [48]

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8 0
3 years ago
a compound has 15.39 g of gold for every 2.77 g of chlorine. simplified there is _____ g of gold for every 1 g of chlorine
iren [92.7K]

Answer:

There is 5.56 g of gold for every 1 g of chlorine

Explanation:

The ratio is the relationship between two numbers, defined as the ratio of one number to the other. So, the ratio between two numbers a and b is the fraction \frac{a}{b}

You know that a compound has 15.39 g of gold for every 2.77 g of chlorine. This can be expressed by the ratio:

\frac{15.39 g  of gold}{2.77 g of chlorine}

The proportion is the equal relationship that exists between two reasons and is represented by:    \frac{a}{b}=\frac{c}{d}

This reads a is a b as c is a d.

To calculate the amount of gold per 1 g of chlorine, the following proportion is expressed:

\frac{15.39 g  of gold}{2.77 g of chlorine}=\frac{mass of gold}{1 g of chlorine}

Solving for the mass of gold gives:

mass of gold=1 g of chlorine*\frac{15.39 g  of gold}{2.77 g of chlorine}

mass of gold= 5.56 grams

So, <u><em>there is 5.56 g of gold for every 1 g of chlorine</em></u>

5 0
2 years ago
An atom was observed with +3 charge, n = 38, and e = 28. What is the mass number of the atom?
Finger [1]

Answer: 66

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3 0
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V2 = ?

applying Boyle's Law

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V2 = 760 torr * 30 mL / 1520 torr

( C ) is correct

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3 years ago
Identify the parts of the telescope.
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2 years ago
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