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Sveta_85 [38]
3 years ago
14

What mass of Na2SO4 is needed to make 2.0 L of 3.0 M solution (Na = 23 g; S = 32 g; O = 16 g)

Chemistry
2 answers:
Leno4ka [110]3 years ago
8 0

Answer:

852g

Explanation:

From the question given, we obtained the following information:

Molarity = 3M

Volume = 2L

Mole =?

First, we need to find the number of mole of Na2SO4 present in 2L of the solution. This is achieved by doing the following:

Molarity = mole /Volume

Mole = Molarity x Volume

Mole = 3 x 2 = 6moles

Next, we'll find the molar mass of Na2SO4, as illustrated below:

Molar Mass of Na2SO4 = (23x2)+32+(16x4) = 46 + 32 + 64 = 142g/mol

Recall:

Number of mole = Mass /Molar Mass

Mass = number of mole x molar Mass

Mass = 6 x 142 = 852g

Ira Lisetskai [31]3 years ago
8 0

Answer:

710g

Explanation:

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BRAINLIEST PLEASE!!!

A = Smooth Endoplasmic Reticulum

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Explanation:

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4 0
2 years ago
What is the atomic number for neon?
Anna35 [415]
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4 0
3 years ago
Give the coordination number of the central metal ion in the following complex ions.
melomori [17]

Answer:

a). Coordination no. of [Ni(en)_2(NH_3)_2]^2+ = 6

b). Coordination no. of [Fe(en)(ox)Cl_2]^2- = 6

Explanation:

Coordination number is defined as number of donar atoms bonded to the central atom of the complex ion.

a). Coordination no. of [Ni(en)_2(NH_3)_2]^2+ = 6

en or ethylenediamine is a bidentate ligand.

In bidentate ligand, two atoms directly bonded to the central atom.

NH3 is a unidentate ligand.

So, coordination no.= No. of bidentate ligand x 2 + No. of unidentate ligand

                                = 2\times 2 + 2 = 6

b). Coordination no. of [Fe(en)(ox)Cl_2]^2- = 6

Ethylenediamine (en) is a bidentate ligand.

oxalate ion (ox) is also a bidentate ligand.

Cl is a unidentate ligand

So, coordination no.= No. of bidentate ligand x 2 + No. of unidentate ligand

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8 0
3 years ago
Suppose you wanted to dissolve 40.0 g NaOH in enough H2O to make 6.00 dm3 of solution
dezoksy [38]

Molarity of solution = 1.6 M

<h3>Further explanation</h3>

Given

40 g NaOH

6 L solution

Required

Steps to solve the problem of molarity

Solution

No additional information about the question.

If you want to make the solution above, then we just need to put the existing NaOH (40 g) into 6 L of water, then do the stirring (in a warm temperature above the hot plate will speed up the NaOH dissolving process)

But if you want to know the molarity of a solution, then

  • 1. we calculate the moles of NaOH

\tt mol=\dfrac{mass}{MW}

MW(molecular weight) of NaOH=

Ar Na+ Ar O + Ar H

23 + 16 + 1 = 40 g/mol

so mol NaOH :

\tt mol=\dfrac{40~g}{40~g/mol}=1~mol

  • 2. Molarity(M)

\tt M=\dfrac{n}{V}\\\\M=\dfrac{1}{6}\\\\M=0.16

5 0
3 years ago
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