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3 years ago

What are answers to the questions shown below?

Chemistry

1 answer:

AleksAgata [21]3 years ago

8 0

Answer:

Explanation:

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20. Earth's tallest mountain ranges are formed at _______ plate boundaries. A. continental-continental B. oceanic-oceanic C. oce

ziro4ka [17]

I believe that the answer is A, continental-continental.

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3 years ago

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How many moles of sodium hydroxide would react with 1 Mole of sulphuric acid?

Paul [167]

Answer:

Two moles.

Explanation:

Sulphuric (sulfuric) acid $\rm H_2SO_4$ is a diprotic acid. When one mole of $\rm H_2SO_4$ molecules dissolve in water, two moles of $\rm H^{+}$ ions would be produced.

$\rm H_2SO_4 \to 2\, H^{+} + {SO_4}^{2-}$ .

On the other hand, sodium hydroxide $\rm NaOH$ is a monoprotic base. When one mole of $\rm NaOH$ formula units dissolve in water, only one mole of hydroxide ions $\rm OH^{-}$ would be produced.

$\rm NaOH \to Na^{+} + OH^{-}$ .

Note that $\rm H^{+}$ and $\rm OH^{-}$ react at a one-to-one ratio:

$\rm H^{+} + OH^{-} \to H_2O$ .

As a result, it would take $2\; \rm mol$ of $\rm OH^{-}$ to react with the $\rm 2\; mol$ of $\rm H^{+}$ that was released when $1\; \rm mol$ of $\rm H_2SO_4$ is dissolved in water. Since one mole of $\rm NaOH$ formula units could produce only one mole of $\rm OH^{-}$ , it would take $\rm 2\; mol$ of $\rm NaOH$ formula units to produce that $2\; \rm mol$ of $\rm OH^{-}$ for reacting with $1\; \rm mol$ of $\rm H_2SO_4$ .

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3 years ago

An electromagnet works because ________

Gnoma [55]

I believe this answer is A. Moving electrons generate magnetic forces. Hope this helps!!! :)

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3 years ago

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What might happen if you got too close to the center of the Milky Way galaxy?

Lady_Fox [76]

Answer:

you would be trapped in the gravitational pull of a black hole

Explanation:

there is a black hole in the center of the galacy

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3 years ago

Calculate the p value of each ion indicated:

Nataliya [291]

27/208 = normality

12 x 10^-2 approx = normality

nw Ka = 14.3 x 10^-3

pKa = 3 - log 14

now, after getting the pKa put it in formula :
pH = pKa + log concn of ion/concn of salt and you'll get it

hope this helps

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3 years ago