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3 years ago

What is the median ?

Mathematics

1 answer:

mel-nik [20]3 years ago

7 0

The median value of a range of values.

denoting or relating to a value or quantity lying at the midpoint of a frequency distribution of observed values or quantities, such that there is an equal probability of falling above or below it.

a straight line drawn from any vertex of a triangle to the middle of the opposite side.

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35 lbs of apples cost $420. <br> How much would 6 lbs cost?

Ymorist [56]

Answer:

$72

Step-by-step explanation:

one lb costs $12 so just multiply it by 6

3 0

3 years ago

Read 2 more answers

What is the side length of a cube with a volume of 216 cubic units?

hichkok12 [17]

Hey there!!

The area for the volume of a cube -

s³ , s = side

volume = 216

s³ = 216

s = ∛216

s = 6

The required answer is 6

Hope my answer helps!

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3 years ago

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Choose the correct proportions.

ozzi

Answer:

Step-by-step explanation:

We know that the only possibilities with proportionate answers are 6:7 = 12:14, or 7:6 = 14:12. Only 6:7 = 12:14 is an answer choice. Both the numbers in the first pair times two equal the second pair.

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3 years ago

Richard is given one of four pieces of equal-sized fabric. After using some of his fabric for a project, he has 5/6 of a square

ValentinkaMS [17]

Answer:

Richard used $2\frac{1}{12}\ yd ^2$ of fabric for his project.

Step-by-step explanation:

Given:

Total amount of fabric = $11\frac23\ yd^2$

Now To convert a mixed fraction to an improper fraction, Multiply the whole number part by the fraction's denominator, Add that to the numerator,Then write the result on top of the denominator.

$11\frac23\ yd^2$ can be Rewritten as $\frac{35}{3}\ yd^2$

Number of pieces fabric was cut = 4

Richard is given one of four pieces of equal-sized fabric.

Amount of fabric Richard was given = $\frac14 \times \frac{35}{3}=\frac{35}{12}\ yd^2$

Amount of fabric left with Richard = $\frac56 \ yd^2$

We need to find the amount of fabric Richards used for his project.

Solution:

Now we can say that;

amount of fabric Richards used for his project is equal to Amount of fabric Richard was given minus Amount of fabric left with Richard.

framing in equation form we get;

amount of fabric Richards used for his project = $\frac{35}{12}-\frac56$

Now we will make the denominator common using LCM we get;

amount of fabric Richards used for his project = $\frac{35}{12}-\frac{5\times2}{6\times2} = \frac{35}{12}-\frac{10}{12}$

Now Denominator is same so we will solve the numerator.

amount of fabric Richards used for his project = $\frac{35-10}{12}= \frac{25}{12}\ yds^2$

$\frac{25}{12}\ yds^2$ can be rewritten as $2\frac{1}{12}\ yd ^2$

Hence Richard used $2\frac{1}{12}\ yd ^2$ of fabric for his project.

7 0

3 years ago

Please help with at least one question.

Cloud [144]

Okay, first off negative is well negative and since there is no other negatives, -5/7 is least (making it go first). Second, what is smaller 3/5 or 2/9, remember that the bigger the denominator the smaller the piece.

[/] [/] [/] [] [] = 3/5

[/] [/] [] [] [] [] [] [] [] 2/9

At the end it should be -5/7, 2/9 , 3/5. This method can go the same for problems like these...Hope it helps!

7 0

3 years ago