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Zinaida [17]
2 years ago
10

what is the specific heat of iron if 985 J of energy is required to raise the temperature of 158.5 g from 10.0°C to 24.0° C ?​

Chemistry
1 answer:
Alexus [3.1K]2 years ago
7 0

Answer: 0.44

Explanation:

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determine the molecular formula of the compound with an empirical formula of CH and a molar mass of 78.110g/mol
Vlada [557]

Answer:

C_{6} H_{6}

Explanation:

First, find the mass of empirical formula, CH. 12.01 g/mol is for carbon, and 1.008 g/mol is for hydrogen. 12.01+1.008=13.018 G/mol CH. Divide 78.110 G/mol by 13.018 g/mol. You get approximately 6. Multiply that by the subscript of each element. 6(CH)=

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3 years ago
based on the positions in the periodic table, which two elements would mostly readily combine to make a stable compound
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3 years ago
The vapor pressure of benzene is 73.03 mm Hg at 25°C. How many grams of estrogen (estradiol), C18H24O2, a nonvolatile, nonelectr
alexira [117]

Answer:

14.9802 grams of estrogen must be added to 216.7 grams of benzene.

Explanation:

The relative lowering of vapor pressure of solution containing non volatile solute is equal to mole fraction of solute.

\frac{p_o-p_s}{p_o}=\frac{n_2}{n_1+n_2}

Where:

p_o = Vapor pressure of pure solvent

p_s = Vapor pressure of the solution

n_1 = Number of moles of solvent

n_2 = Number of moles of solute

p_o = 73.03 mmHg

p_s= 71.61 mmHg

n_1=\frac{216.7 g}{78.12 g/mol}=2.7739 mol

\frac{73.03 mmHg-71.61 mmHg}{73.03 mmHg}=\frac{n_2}{2.7739 mol+n_2}

n_2=0.05499 mol

Mass of 0.05499 moles of estrogen :

= 0.05499 mol × 272.4 g/mol = 14.9802 g

14.9802 grams of estrogen must be added to 216.7 grams of benzene.

6 0
3 years ago
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