1250 J in 5 sec= 250 Joule(s) per second (1250/5 0
250 Joules per second = 250 Watts ( 1J/s = 1 Watt per definition)
250 Watts output = 250/0.65 efficiency = 384 Watts input
1 Horsepower = 732 Watts
Motors 1 Horsepower and under are made in certain step sizes like
3/4 , 1/2 , 1/3, 1/4, 1/16 1/20 of a Horsepower.
3/4 Horsepower is 549 Watts
1/2 Horsepower is 366 Watts
so you need to 3/4 horsepower motor to achieve 1250 J of work in 5 seconds.
Answer:
L = 22.97 H
Explanation:
Given that,
Capacitance, 
Oscillation frequency, f = 0.5 Hz
The frequency of an AC circuit is given by :

Where
L is impedance

So, the impedance of LC circuit 22.97 H.
U can do what is the strongest paper towel
Answer:
you should write about a book you read
Explanation:
because maybe you got really good things in it
or here is an example
Police siren is the correct answer. Hope this helps.