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3 years ago

Ground infrared telescopes Versailles at high altitude and dry climate. What explains the location for those infrared telescopes

Physics

1 answer:

Natali5045456 [20]3 years ago

3 0

Answer:

High altitude

Explanation:

Infrared rays are absorbed by water vapor in the lower parts of our atmosphere such as near the sea level.Infrared telescopes positioned on high mountains can observe the cosmos at a wavelength near-infrared. In this case, this telescope is positioned on a mountain top where the altitude is high.

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A monochromatic light passes through a narrow slit and forms a diffraction pattern on a screen behind the slit. As the slit widt

maw [93]

Answer:

shrinks with all the fringes getting narrower

Explanation:

As the light passes through the slit, the diffraction pattern shrinks, as the waves have more opening to penetrate, and the fringes becomes more narrow as a result of that, The opposite happens as the conditions are reversed.

8 0

3 years ago

A sphere is charged with electrons to -6 x 10^-6C. How many electrons make up this charge? The elemental charge is 1.6 x 10^-19

just olya [345]

Answer:

$3.75*10^{-13}$ electrons

Explanation:

The total charge Q is the sum of the charge of the N electrons contained in the sphere:

$Q=N*q_{e}$

$q_{e}=-1.6*10^{-19}C$ charge of a electron

We solve to find N:

$N=\frac{Q}{q_{e}}=\frac{-6 x 10^{-6}}{-1.6 x 10^{-19}}=3.75*10^{-13}$

7 0

3 years ago

What is the square root of pi

rosijanka [135]

Answer: The square root of Pi is 1.77245.

Please mark as brainliest

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3 years ago

Refraction occurs when a wave changes______ as it passes through a different medium.

Alexandra [31]

The answer to your question is Speed

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2 years ago

A soft tennis ball is dropped onto a hard floor from a height of 1.50 m and rebounds to a height of 1.10 m. (a) Calculate its ve

Gemiola [76]

Answer:

(a) v = 5.42m/s

(b) vo = 4.64m/s

(d) Δy = 5.11*10^-3m

Explanation:

(a) The velocity of the ball before it hits the floor is given by:

$v=\sqrt{2gh}$ (1)

g: gravitational acceleration = 9.8m/s^2

h: height where the ball falls down = 1.50m

$v=\sqrt{2(9.8m/s^2)(1.50m)}=5.42\frac{m}{s}$

The speed of the ball is 5.42m/s

(b) To calculate the velocity of the ball, after it leaves the floor, you use the information of the maximum height reached by the ball after it leaves the floor.

You use the following formula:

$h_{max}=\frac{v_o^2}{2g}$ (2)