Answer:
The work done on the athlete is approximately 2.09 J
Explanation:
From the definition of the work done by a variable force:
and substituting with the function of our problem:
A string is attached to a vibrating machine that has a frequency of 120 Hz. The other end of the string is passed over a pulley
1 answer:
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Answer:
T = 76.39°C
Explanation:
given,
coffee cup temperature = 95°C
Room temperature= 20°C
expression
temperature at t = 0
T(0) = 95°C
temperature after half hour of cooling
t = 30 minutes
T(30) = 61.16° C
average of first half hour will be equal to
T = 76.39°C
Hey there!
Your correct answer would be (<span>Every mass exerts a gravitational force on every other mass.) It really doesn't matter the size in mass what so ever, gravity is stronger than mass, mass in nothing compared to mass. Therefor, gravity exert's mass on any object with any size of mass.
Your correct answer would be . . .
</span>
<span>
Hope this helps.
~Jurgen</span>
Your correct answer would be (<span>Every mass exerts a gravitational force on every other mass.) It really doesn't matter the size in mass what so ever, gravity is stronger than mass, mass in nothing compared to mass. Therefor, gravity exert's mass on any object with any size of mass.
Your correct answer would be . . .
</span>
<span>
Hope this helps.
~Jurgen</span>