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Pie
2 years ago
6

A string is attached to a vibrating machine that has a frequency of 120 Hz. The other end of the string is passed over a pulley

of negligible mass and friction and is attached to a weight hanger which holds a mass m=0.5kg. What is the tension in newtons?
Physics
1 answer:
BabaBlast [244]2 years ago
4 0

Answer:

Explanation:

Given that,

The frequency of vibration is 120Hz

The mass of object attached is 0.5kg.

We want to find the tension In the string

The tension in the string is the weight of the object, it is how much gravity is pulling the object to the centre of the earth

Using newton second law.

F_net = m•a_y

The body is not accelerating the y-direction, then, a_y = 0

F_net = 0

Force acting on the string is the weight of the object and the tension in the string

T - W = 0

T = W

Where weight is mass × gravity

W = mg

Then,

T = W = mg

T = mg = 0.5 × 9.81

T = 4.905 N

The tension in the string is 4.905 N

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6 0
1 year ago
The moon Umbriel orbits Uranus (mass = 8.68 x 10^25 kg) at a distance of 2.66 x 10^8 m. What is Umbriel's orbital period (in hou
Whitepunk [10]

Answer:

T = 99.51 hour

Explanation:

Mass of Uranus, M=8.68\times 10^{25}\ kg

The moon Umbriel orbits Uranus at a distance of 2.66\times 10^8\ m

We need to find Umbriel's orbital period. Let it is T. Using Kepler's third law of motion to find it.

T^2\propto r^3\\\\T^2=\dfrac{4\pi^2r^3}{GM}\\\\T^2=\dfrac{4\pi^2\times (2.66\times 10^8)^3}{6.67\times 10^{-11}\times 8.68\times 10^{25}}\\\\T=358244.51\ s

As 1 hour = 3600 s

358244.51 s = 99.51 hour

Hence, Umbriel's orbital period is 99.51 hour.

7 0
2 years ago
Sara is riding her bike down the road at 35 km/hr. She starts to peddle faster as she
steposvetlana [31]

Answer:

Distance covered to top of the hill was : 1.755 km

Explanation:

Initial velocity = 35 km/hr

Acceleration = 2.0 km/hr²

Time taken to accelerate = 3 minutes = 3/60 hours = 1/20 hours

Formula for acceleration : a = Δv /t  

v-u/t    ---where u is initial velocity , v is final velocity and t is time taken for acceleration

v- 35 / 0.05 = 2

v = 35.10 km/h

Formula for distance is product of speed and time

Distance covered = 35.10 * 0.05 = 1.755 km

6 0
2 years ago
An electric motor rotating a workshop grinding wheel at a rate of 151 rev/min is switched off. Assume constant angular decelerat
tamaranim1 [39]

Answer:

Explanation:

Initial angular velocity ω₀ = 151 x 2π / 60

= 15.8  rad /s

final velocity = 0

Angular deceleration α = 2.23 rad / s

ω² = ω₀² -  2 α θ

0 = 15.8² - 2 x 2.23 θ

= 55.99  rad

one revolution = 2π radian

55.99 radian = 55.99  / 2 π no of terns

= 9 approx .

8 0
3 years ago
What happens when you compress a gas?
8090 [49]
The density increases.
When gases are compressed, their volume decreases, and the resulting pressure increases. The temperature will change if either P or V are held constant. Since the volume decreases, then density, or m/V, increases.
P×V ~ T
8 0
3 years ago
Read 2 more answers
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