Answer:
a
The New angular speed is 
b
The Kinetic energy before the masses are pulled in is 
c
The Kinetic energy after the masses are pulled in is 
Explanation:
From the we are told that masses are 1.08 m from the axis of rotation, this means that
The radius
The mass is 
The angular speed 
The moment of inertia of the system excluding the two mass 
New radius 
Generally the conservation of angular momentum can be mathematical represented as
![w_f = [\frac{I_i}{I_f} ]w_i .....(1)](https://tex.z-dn.net/?f=w_f%20%3D%20%5B%5Cfrac%7BI_i%7D%7BI_f%7D%20%5Dw_i%20.....%281%29)
Where
is the final angular speed
is the initial angular speed
is the initial moment of inertia
is the final moment of inertia
Moment of inertia is mathematically represented as

Where I is the moment of inertia
m is the mass
r is the radius
So the Initial moment of inertia is given as


The multiplication by is because we are considering two masses
![I_i = 2 [(3.09)(1.08)^2] +3.25 = 10.46 kg \cdot m^2](https://tex.z-dn.net/?f=I_i%20%3D%202%20%5B%283.09%29%281.08%29%5E2%5D%20%2B3.25%20%3D%2010.46%20kg%20%5Ccdot%20m%5E2)
So the final moment of inertia is given as
Substituting these values into equation 1
Generally Kinetic energy is mathematically represented in term of moment of inertia as

Now considering the kinetic energy before the masses are pulled in,

The Moment of inertia would be
The Angular speed would be
Now substituting these value into the equation above

Now considering the kinetic energy after the masses are pulled in,

The Moment of inertia would be
The Angular speed would be
Now substituting these value into the equation above