Two planets of the same mass are observed.

2 answers:

6 0

It really doesn't matter what mass the planets have, or whether they're equal, or whether they're planets. The farther apart two objects are, the less gravitational attraction there is between them.

Oliga [24]3 years ago

5 0

As the distance increases, the gravitational force between them decreases.
So, the option with the largest distance is (A) 90 light yrs. And that's the answer !!

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. Which of the following are forces that push upward on an indoor skydiver? Choose all that apply. *

SpyIntel [72]

The forces that push upward on an indoor skydiver are lift force and air resistance.

The forces that act on a skydiver moving downwards includes, gravity due to his weight, air resistance and lift force.

The downward forces on the indoor skydiver include the following;

gravity due to its weight
downward force due its acceleration

The upward force on the indoor skydiver include the following;

lift force
air resistance

Thus, we can conclude that the forces that push upward on an indoor skydiver are lift force and air resistance.

Learn more here:brainly.com/question/8947470

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3 years ago

Which would take more force to stop in 17. 3 seconds: a 3. 2 kg ball rolling in a straight line at a speed of 0. 3 m/sec or a 4.

Molodets [167]

The second one (4.1 kg ball)

This is because the mxv is greater than the other one.

For the 4.1kg ball, the force it’s moving on is 4.92N

As for the 3.2kg ball, it’s moving with a force of 0.9N. Much less than the other one.

4 0

2 years ago

Choose heated air or cooled air for the following atmospheric property term: rises

inysia [295]

I'm not really sure what you mean, but it could be heated air because 'rises' could mean temperature rising, and when temperature rises, the air heats up... i hope I'm correct and this helps you. correct me if I'm wrong.

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3 years ago

Frequency of the wave below?

agasfer [191]

It's hard to tell exactly what's happening in that 110 cm that you marked over the wave. What is under the ends of the long arrow ? How many complete waves ? I counted 4.5 complete waves ... maybe ?

If there are 4.5 complete waves in 110cm, then the length of 1 wave is (110/4.5)=24.44cm.

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Frequency = 2m/s /0.2444m

Frequency = 8.18 Hz

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jeyben [28]

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