As our story begins, the sled ... whose mass is 8 kg ... is sliding along the ice at a speed of 4 m/s.
The sled's kinetic energy is (1/2 m v²) = (4 kg · 16 m²/s²) = 64 J .
After what seems like only the blink of an eye, the sled is no longer sliding. It is stationary. Motionless. At Rest. Just sitting there !
Its speed has been reduced to zero and ... because kinetic energy is the energy of motion ... the sled's kinetic energy is now also zero. Sixty-four Joules of energy have disappeared !
How can this be ? ! ? We know that energy is conserved. It can never just appear out of nothing, and it can never just disappear into nothing. If energy suddenly appears, it had to come from somewhere, and if energy suddenly disappears, it had to go somewhere. So where did our 64 Joules of kinetic energy go ?
It went into the ice, THAT's where ! We can say that the sled did 64J of work, and melted a thin slick layer of water on the surface of the ice. OR we can say that friction did NEGATIVE 64J of work on the sled, to cancel the 64J that it had originally, sap its kinetic energy, and bring it to rest.
I think <em>choice-B</em> was supposed to say "<em>B. -64J</em>", but somebody typed it sloppily and neglected to proofread it before posting.
Answer
given,
mass of the stick = 290 grams = 0.29 Kg
Force on the stick on one side = F = 9 N
force acting perpendicular to stick.
magnitude of acceleration
rate of change of angular momentum is equal to Force
rate of change of angular momentum = 9 N
F = m a
a = 31.034 m/s²
Direction of motion will in the direction of force application or in the direction of change of velocity
E, B, C# minor and A for the most songs
The formula for solving voltage is V=IR where V represents the voltage, where "I" represent the current and R represents the resistance. Then, the given values are enumerated below and these will help us in solving for the unknown.
V=10 volts
I=?
R=2 ohms
V=IR
I=V/R
I=10/2
I=5 amperes
Therefore, the current is 5 amperes.
Answer:Sometime decreases and sometime increases.
Explanation:
Given
Projectile is launched at 
so horizontal velocity=ucos35
vertical velocity=usin35
since gravity acts in the vertical direction, therefore, it affects only the vertical component of the projectile.
So Vertical velocity first decrease up to maximum height and then starts to increase.
