Chemical reaction: Sr(OH)₂ + 2HNO₃ → Sr(NO₃)₂ + 2H₂O.
part A) m(Sr(OH)₂) = 21,78 g.
n(Sr(OH)₂) = m(Sr(OH)₂) ÷ M(Sr(OH)₂).
n(Sr(OH)₂) = 21,78 g ÷ 87,62 g/mol.
n(Sr(OH)₂) = 0,248 mol.
c(Sr(OH)₂) = n(Sr(OH)₂) ÷ V(Sr(OH)₂).
c(Sr(OH)₂) = 0,248 mol ÷ 0,075 L.
c(Sr(OH)₂) = 3,3 mol/L.
part B) V(Sr(OH)₂) = 34,21 mL = 0,03421 L.
n(Sr(OH)₂) = 0,03421 L · 3,3 mol/L = 0,112 mol.
From chemical reaction: n(Sr(OH)₂) : n(HNO₃) = 1 : 2.
n(HNO₃) = 0,225 mol.
V(HNO₃) = 0,225 mol ÷ 0,25 mol/L.
V(HNO₃) = 0,9 L = 900 ml.
4 carbon chain is butane. With a triple bond it is butane. Since the triple bond is on the first carbon it can be called 1-butyne, or but-1-yne.
Answer:
D. CF₄
Explanation:
The compound with this molecular geometry is Carbon tetrafluoride (CF₄)
Carbon tetrafluoride (CF₄) also known as Tetrafluoromethane, is known to be the simplest perfluorocarbon. The compound, tetrafluoromethane is the hydrocarbon methane has been perfluorinated. It useful as a refrigerant but known to be a greenhouse gas. Due to the nature of the carbon-flourine bond, it has very high bonding strength. Its bonds are known to be the strongest single bonds in organic chemistry.
Option D is the correct answer.
Answer: I think you have to subtract the distances
Explanation:
It is a value (of 1/2) that describes the angular momentum of an electron in either clockwise or in anti-clockwise direction..........
