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3 years ago

Animals marking their territory with urine is an example of _______.

1 answer:

7 0

The answer is competition. It's competition because they are protecting their territory, so their way of protecting or fighting for their territory is to urinate on their territory. By a way of showing that they don't want nobody in their territory.

You might be interested in

What is the maximum number of electrons in an atom n=4 l=1 ml=0

Nitella [24]

Answer:

18 electrons

Explanation:

when l=1, this tell you that it is "p sub shell"

4 0

3 years ago

Which of these choices is the best definition of absolute dating?

skad [1K]

Answer:

I think it's A because the sedimentary rock is also involved in finding the fossils to determine their phenotype and their roots.

4 0

3 years ago

A gate made of painted iron is beginning to rest in areas where the paint has worn away why is the formation of rust considered

Pavel [41]

Answer:

because it is two substances reacting together to create a new substance

Explanation:

when iron rusts, iron molecules react with the oxygen molecules creating iron oxide aka rust.

3 0

3 years ago

Anabolic steroids are sometimes used illegally by athletes to increase muscle strength. A forensic chemist analyzes some tablets

11111nata11111 [884]

Answer:

The empirical formula is = $C_{10}H_{14}O$

The formula of steroid = $C_{20}H_{28}O_2$

Explanation:

Mass of water obtained = 1.007 g

Molar mass of water = 18 g/mol

Moles of $H_2O$ = 1.007 g /18 g/mol = 0.0559 moles

2 moles of hydrogen atoms are present in 1 mole of water. So,

Moles of H = 2 x 0.0559 = 0.1119 moles

Molar mass of H atom = 1.008 g/mol

Mass of H in molecule = 0.1119 x 1.008 = 0.1128 g

Mass of carbon dioxide obtained = 3.516 g

Molar mass of carbon dioxide = 44.01 g/mol

Moles of $CO_2$ = 3.516 g /44.01 g/mol = 0.0799 moles

1 mole of carbon atoms are present in 1 mole of carbon dioxide. So,

Moles of C = 0.0799 moles

Molar mass of C atom = 12.0107 g/mol

Mass of C in molecule = 0.0799 x 12.0107 = 0.9595 g

Given that the steroids only contains hydrogen, oxygen and carbon. So,

Mass of O in the sample = Total mass - Mass of C - Mass of H

Mass of the sample = 1.200 g

Mass of O in sample = 1.200 - 0.9595 - 0.1128 = 0.1277 g

Molar mass of O = 15.999 g/mol

Moles of O = 0.1277 / 15.999 = 0.00798 moles

Taking the simplest ratio for H, O and C as:

0.1119 : 0.00798 : 0.0799

= 14 : 1 : 10

The empirical formula is = $C_{10}H_{14}O$

Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,

Molecular mass = n × Empirical mass

Where, n is any positive number from 1, 2, 3...

Mass from the Empirical formula = 10×12 + 14×1 + 16= 150 g/mol

Molar mass = 300.42 g/mol

So,

Molecular mass = n × Empirical mass

300.42 = n × 150

⇒ n = 2

The formula of steroid = $C_{20}H_{28}O_2$

6 0

4 years ago