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2 years ago

Animals marking their territory with urine is an example of _______.

1 answer:

7 0

The answer is competition. It's competition because they are protecting their territory, so their way of protecting or fighting for their territory is to urinate on their territory. By a way of showing that they don't want nobody in their territory.

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An iron smoothing out the wrinkles in pants ? CONVECTION,RADIATION,CONDUCTION?

nexus9112 [7]

Answer:

Conduction i think-

3 0

2 years ago

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If you have a density of 3g/meander a mass of 15g what is the volume?

erma4kov [3.2K]

M=D*V,
V=m/D
m=15 g
D=3 g/ml
V=15 g/3 g/ml=5 ml

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3 years ago

An element has an atomic number of 30. How many protons and electrons are in a neutral atom of the element? A. 30 protons, 30 el

Minchanka [31]

Atomic number shows the number of protons in an atom's nucleus. If the atomic number is 30, then it has 30 protons. The question says it is neutral, so it must have the same amount of protons and electrons.

A is the correct answer based on this.

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3 years ago

How many moles are in 99.5 grams of titanium? Round your answer to the nearest hundredth. Be sure to include units.

AlekseyPX

Answer:

1000

Explanation:

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2 years ago

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A cubic piece of platinum metal (specific heat capacity = 0.1256 J/°C･g) at 200.0°C is dropped into 1.00 L of deuterium oxide ('

polet [3.4K]

Answer:

$a=5.65cm$

Explanation:

Hello,

In this case, for this heat transfer process in which the heat lost by the hot platinum is gained by the cold deuterium oxide based on the equation:

$Q_{Pt}=-Q_{Deu}$

We can represent the heats in terms of mass, heat capacities and temperatures:

$m_{Pt}Cp_{Pt}(T_f-T_{Pt})=-m_{Deu}Cp_{Deu}(T_f-T_{Deu})$

Thus, we solve for the mass of platinum:

$m_{Pt}=\frac{-m_{Deu}Cp_{Deu}(T_f-T_{Deu})}{Cp_{Pt}(T_f-T_{Pt})} \\\\m_{Pt}=\frac{-1.00L*1110g/L*4.211J/(g\°C)*(41.9-25.5)\°C}{0.1256J/(g\°C)*(41.9-200.0)\°C} \\\\m_{Pt}=3860.4g$

Next, by using the density of platinum we compute the volume:

$V_{Pt}=\frac{3860.4g}{21.45g/cm^3}\\ \\V_{Pt}=180cm^3$

Which computed in terms of the edge length is:

$V=a^3$

Therefore, the edge length turns out:

$a=\sqrt[3]{180cm^3}\\ \\a=5.65cm$

Best regards.

6 0

3 years ago