Given :
Two forces act on a 6.00-kg object. One of the forces is 10.0 N.
Acceleration of object 2 m/s².
To Find :
The greatest possible magnitude of the other force.\
Solution :
Let, other force is f.
So, net force, F = 10 + f.
Now, acceleration is given by :
Therefore, the greatest possible magnitude of the other force is 2 N.
Hence, this is the required solution.
Answer:
which of the cars are speeding up: c
which of the cars or slowing down: a
which of the cars are maintaning a constant speed: b
Explanation:
Answer:
v = 8.45 m/s
Explanation:
given,
mass = 3 kg
angle = 30.0°
vertical distance = 3.3 m
μ = 0.06
according to conservation of energy
KE(loss) = PE(gain) + Work done (against\ friction)..............(1)
frictional Force
work against friction
W = F d
Potential energy
PE = mgh
v = 8.45 m/s
the minimum speed is equal to 8.45 m/s
The answer is: [D]: "the position of the moon each month in relation to THE SUN AND THE MOON" .
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Note of interest: The origin of the word "month" was: "moon-th" — but shortened to "month" — (no coincidence!).
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Answer:
exothermic
Explanation:
energy is absorbed by the surroundings
