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Natali [406]
3 years ago
12

Help please:A boy weighing 30 kg rides a scooter. The total kinetic energy of the boy and the scooter is 437.6 J. Determine the

speed at which the boy moves if the mass of the scooter is 5kg?​
Physics
2 answers:
Ksenya-84 [330]3 years ago
5 0

Answer:

the total mass is 35 kg

k.E = 1/2 mv2

43.76 =1/2 v2

v2=2×43.76

Explanation:

v=radicls 87.52 which is equal to 9.5 m/s

larisa86 [58]3 years ago
3 0

Answer:

5 m/s

Explanation:

Mass of the boy + scooter system =  35 kg

Kinetic Energy =  437.6 J

437.6 = \frac{1}{2} 35 {v}^2

25.0057143 = v^{2}

v = 5 m/s

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6 0
3 years ago
The breaking in (blank) bonds in food releases energy for your body to use
kicyunya [14]

Answer:

The breaking in <em>molecular</em> bonds in food releases energy for your body to use.

5 0
2 years ago
A student throws a small rock straight upwards. The rock rises to its highest point and then falls back down. How does the speed
Vladimir [108]

Answer:

we assume that it starts with a velocity of 10m/s. At 2m height above ground level, its velocity decreases at 3m above ground level

for its way down the velocity at 3m on its way down is more than its velocity at 2m on its way down.

Explanation:

A student throws a small rock straight upwards. The rock rises to its highest point and then falls back down. How does the speed of the rock at 2m on the way down compare with its speed at 2m on the way up?

It decreases in speed on its way down and increases in speed on its way down.

it decreases in speed on its way up because the the vertical motion is against the earths gravitational pull on an object to the earth's center

.It increases in speed on his way down because its under the influence of gravity

from newton's equation of motion we can check by

using V^2=u^2+2as

we assume that it starts with a velocity of 10m/s. At 2m height above ground level, its velocity decreases at 3m above ground level

for its way down the velocity at 3m on its way down is more than its velocity at 2m on its way down.

5 0
3 years ago
A 1000.kg car moving at north at 100. km/hr brakes to a stop in 50. m within a uniform acceleration. what are magnitude and dire
Marianna [84]

Answer:

Force=7.71KN in the opposite direction

Explanation:

Given the mass of the car(M)=1000Kg

The initial speed of the car(u)=100km/hr

we know that 1km/hr=5/18 m/sec

100km/hr=100*5/18 m/sec=27.77m/sec

the distance travelled before it stops (s)=50m

let the acceleration of the car be a

The final velocity of the car is 0.

we know that  v^{2}-u^{2}=2as

0^{2}-27.77^{2}=2(-a)(50)

a=7.712m/sec^{2}

We know that F=Ma

F=1000* 7.712=7712N=7.71KN

6 0
3 years ago
A car starting from rest accelerated at a rate of 0 .5 m/s up to 2 km what would be the final velocity of the car and how much t
Julli [10]

From equation of motion v^2 = u^2 +2aS

Hence, the final velocity is 40 m/s.

<em><u>hope </u></em><em><u>it's </u></em><em><u>help </u></em><em><u>you</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>! </u></em>

<em><u>#</u></em><em><u>rishu</u></em>

4 0
3 years ago
Read 2 more answers
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