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leva [86]
2 years ago
15

21. A 1000-kg automobile moving with a speed of 24 m/s relative to the road collides with a 500-kg automobile initially at rest.

If the two stick together, what is the velocity in m/s of the two cars after the collision according to an observer in a truck moving 10 m/s in the same direction as the moving cars
Physics
1 answer:
Luda [366]2 years ago
4 0

A truck is moving with less velocity in the direction in which the truck is moving earlier because the truck has more momentum.

<h3 /><h3>In which direction the truck moves?</h3>

A truck is moving with the velocity of 10 m/s in the same direction in which the truck is moving earlier because the truck has more mass so it has more momentum. Due to collision, the velocity of the truck is slow down but can't be stopped because of high momentum in the truck.

So we can conclude that a truck is moving with less velocity in the direction in which the truck is moving earlier because the truck has more momentum.

Learn more about momentum here: brainly.com/question/7538238

#SPJ1

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DiKsa [7]

Answer:

5,000 meters

Explanation:

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3 years ago
State the conservation of momentum theorem
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Answer:

The total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

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An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.70 mm. A 21
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12353 V m⁻¹ = 12.4 kV m⁻¹

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Electric field between the plates of the parallel plate capacitor depends on the potential difference across the plates and their distance of separation.Potential difference across the plates V over the distance between the plates gives the electric field between the plates. Potential difference is the amount of work done per unit charge and is given here as 21 V. Electric field is the voltage over distance.

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8 0
3 years ago
25 POINTS FOR CORRECT ANSWER
castortr0y [4]
No.  I do not agree with Stefan.  Quite the contrary.  I disagree
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5 0
3 years ago
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A 92kg astronaut and a 1200kg satellite are at rest relative to the space shuttle. The astronaut pushes on the satellite, giving
Harman [31]

Answer:

13.7m

Explanation:

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After the push

m_av_a + m_sv_s = 0

Where m_a = 92kg is the mass of the astronaut, m_s = 1200kg is the mass of the satellite, v_s = 0.14 m/s is the speed of the satellite. We can calculate the speed v_a of the astronaut:

v_a = \frac{-m_sv_s}{m_a} = \frac{-1200*0.14}{92} = -1.83 m/s

So the astronaut has a opposite direction with the satellite motion, which is further away from the shuttle. Since it takes 7.5 s for the astronaut to make contact with the shuttle, the distance would be

d = vt = 1.83 * 7.5 = 13.7 m

4 0
3 years ago
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