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nexus9112 [7]
2 years ago
6

Which of the following is the graph of y = 5?

Mathematics
2 answers:
adoni [48]2 years ago
7 0
Y=5 is a horizontal line at which the y value is always 5, so the answer is D.
Lemur [1.5K]2 years ago
5 0
D. is your answer as it shows a line crossing at the Y-intercept of 5
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A bank is reviewing its risk management policies with regards to mortgages. To minimize the risk of lending, the bank wants to c
Mariana [72]

Answer:

1. $ \mu = \$306,500 $

2. \sigma = \$24,500

3. n = 150

4. $ \mu_{x}= \mu = \$306,500 $

5. \sigma_x = \$ 2,000 \\\\

Step-by-step explanation:

The average mortgage owed by Americans is $306,500, with a standard deviation of $24,500.

From the above information, we know that,  

The population mean is

$ \mu = \$306,500 $

The population standard deviation is

\sigma = \$24,500

Suppose a random sample of 150 Americans is selected

n = 150

Since the sample size is quite large then according to the central limit theorem, the sample mean is approximately normally distributed.

The sample mean would be the same as the population mean  that is

$ \mu_{x}= \mu = \$306,500 $

The sample standard deviation is given by

\sigma_x = \frac{\sigma}{\sqrt{n} }

Where \sigma is the population standard deviation and n is the sample size.

\sigma_x = \frac{24,500}{\sqrt{150} }  \\\\\sigma_x = \$ 2,000 \\\\

Therefore, the required parameters are:

1. $ \mu = \$306,500 $

2. \sigma = \$24,500

3. n = 150

4. $ \mu_{x}= \mu = \$306,500 $

5. \sigma_x = \$ 2,000 \\\\

5 0
2 years ago
Which of these relations on the set {0, 1, 2, 3} are equivalence relations? If not, please give reasons why. (In other words, if
Delicious77 [7]

Answer:

(1)Equivalence Relation

(2)Not Transitive, (0,3) is missing

(3)Equivalence Relation

(4)Not symmetric and Not Transitive, (2,1) is not in the set

Step-by-step explanation:

A set is said to be an equivalence relation if it satisfies the following conditions:

  • Reflexivity: If \forall x \in A, x \rightarrow x
  • Symmetry: \forall x,y \in A, $if x \rightarrow y,$ then y \rightarrow x
  • Transitivity: \forall x,y,z \in A, $if x \rightarrow y,$ and y \rightarrow z, $ then x \rightarrow z

(1) {(0,0), (1,1), (2,2), (3,3)}

(3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)}

The relations in 1 and 3 are Reflexive, Symmetric and Transitive. Therefore (1) and (3) are equivalence relation.

(2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)}

In (2), (0,2) and (2,3) are in the set but (0,3) is not in the set.

Therefore, It is not transitive.

As a result, the set (2) is not an equivalence relation.

(4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}

(1,2) is in the set but (2,1) is not in the set, therefore it is not symmetric

Also, (2,0) and (0,1) is in the set, but (2,1) is not, rendering the condition for transitivity invalid.

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3 years ago
Help help help ASAP math math
Lorico [155]
29 mg = 0.029 g hope this helps
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If f(x)=x^1/2-x and g(x)=2x^3-x^1/2-x, find f(x)-g(x)
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X^1/2 - x
-2x^3 - x^1/2 - x

-2x^3 - 2x
i think this is it
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Find the slope of the line.
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There it is i found it :)

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