If x+z=15x+z=15 and w+y=10w+y=10, what is the value of (3w+3y)(2x+2z)(3w+3y)(2x+2z) ?
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Answer:
A) Quantity x minus 5 over quantity x plus 1, where x≠-1 and x≠-9
Step-by-step explanation:
Simplifying the numerator first:
x² + 4x - 45 using the quadratic formula you get;
(x - 5)(x + 9)
Then simplifying the denominator x² + 10x + 9 using a quadratic formula you get;
(x + 1)(x + 9)
Dividing the numerator and denominator now gives;
Cancelling (x + 9) throughout leaves you with;
The only restrictions here is if x = 1 and 9 which will give an undefined answer.