Energy absorbed by the radiologist is 1.775*10^-6J.
To find the answer, we have to know about the radiation.
<h3>How much energy has she absorbed?</h3>
- We have the expression for dose of absorption as,
where; E is the energy absorbed and m is the mass of the body.
- From the above expression, substituting appropriate values given in the question, we get,
Thus, we can conclude that, the Energy absorbed by the radiologist is 1.775*10^-6J.
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Learn more about the radiation here:
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It’s d because it’s useful output which would be light over total input
7.5/8
Answer:
the shooting angle ia 18.4º
Explanation:
For resolution of this exercise we use projectile launch expressions, let's see the scope
R = Vo² sin (2θ) / g
sin 2θ = g R / Vo²
sin 2θ = 9.8 75/35²
2θ = sin⁻¹ (0.6)
θ = 18.4º
To know how for the arrow the tree branch we calculate the height of the arrow at this point
X2 = 75/2 = 37.5 m
We calculate the time to reach this point since the speed is constant on the X axis
X = Vox t
t2 = X2 / Vox = X2 / (Vo cosθ)
t2 = 37.5 / (35 cos 18.4)
t2 = 1.13 s
With this time we calculate the height at this point
Y = Voy t - ½ g t²
Y = 35 sin 18.4 1.13 - ½ 9.8 1,13²
Y = 6.23 m
With the height of the branch is 3.5 m and the arrow passes to 6.23, it passes over the branch
