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Keith_Richards [23]

3 years ago

5

Two sound waves (wave X and wave Y) are moving through a medium at the same speed. If wave X has a greater frequency than wave Y

, then wave X

1 answer:

____ [38]3 years ago

4 0

Answer:

Wave X has a shorter wavelength.

Explanation:

The relation between the speed of a wave, its wavelength and frequency is given by :

$v=f\lambda$

It can be seen that the relationship between the frequency and wavelength is inverse.

In this problem, it is mentioned that two sound waves (wave X and wave Y) are moving through a medium at the same speed. The frequency of wave X is greater than wave Y. Then it would mean that wave X have shorter wavelength than wave Y (due to inverse relation).

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The heat flux for a given wall is in the x-direction and given as q^n = 11 W/m^2, the walls thermal conductivity is 1.7 W/mK and

MrMuchimi

Answer:

$\frac{dT}{dx} = 6.47 ^oC/m$

Also as we can see the equation that heat flux directly depends on the temperature gradient so more is the temperature gradient then more will be the heat flux.

For positive temperature gradient the heat will flow outwards while for negative temperature gradient the heat will flow inwards

Explanation:

As we know that heat flux is given by the formula

$q^n = K\frac{dT}{dx}$

here we know that

K = thermal conductivity

$\frac{dT}{dx}$ = temperature gradient

now we know that

$q^n = 11 W/m^2$

also we know that

K = 1.7 W/mK

now we have

$11 = 1.7 \frac{dT}{dx}$

so temperature gradient is given as

$\frac{dT}{dx} = \frac{11}{1.7} = 6.47 K/m$

also in other unit it will be same

$\frac{dT}{dx} = 6.47 ^oC/m$

Also as we can see the equation that heat flux directly depends on the temperature gradient so more is the temperature gradient then more will be the heat flux.

For positive temperature gradient the heat will flow outwards while for negative temperature gradient the heat will flow inwards

5 0

3 years ago

A heat pump that operates on the ideal vapor-compression cycle with refrigerant-134a is used to heat a house. The mass flow rate

Savatey [412]

(a)

Use â€œsaturated refrigerant-134a pressure tableâ€, to find $ , h , and of refrigerant-134a, at 320kPa (P) .

$h_{1} h_{g}$ = 251.93kJ/kg

$s_{1} (s_g}$ ) =0.93026 kJ/kg-K

$v_{1}(v_{g})$ =0.063681 m/kg

we solve $h_{6}$ ,

$h_{6}$ = 282.62 kj/kg

$h_{3} (h_{f)}$ = 127.25 kJ/kg

We use this formula for finding $Q_{n}$

$Q_n} =( h_{2} - h_{3} )$

= 38.8 kw

(b)

Find the COP of the heat pump ( $COP_{R}$ ) .

( $COP_{R}$ ) = $q_{L} /w_{in}$

$COP_{R}$ = (282.62 -127.25) / (282.62-251.93)

= 5.06

What is evaporator pressures ?

Valves for regulating evaporator pressure

Although the compressor suction pressure may be lower, evaporator pressure regulation (EPR) valves can be employed in the suction line to prevent the evaporator pressure from dropping below a set or controlled value.

An EPR valve is used for the following tasks:

1. Prevent potential damage to a liquid chilling evaporator from the liquid freezing.

2. Prevent frost from accumulating on an air-cooling evaporator when it is near freezing point or when operation cannot be interrupted by a brief failure.

3. Permit the operation of two or more evaporators with the same compressor at various load temperatures.

4. Vary the evaporator pressure in accordance with a fluctuating load that is managed by the load temperature.

Learn more about evaporator pressures visit this link:

brainly.com/app/ask?q=What+is+evaporator+pressures+

#SPJ4

7 0

1 year ago

The given function represents the position of a particle traveling along a horizontal line. s(t) = 2t3 − 3t2 − 36t + 6 for t ≥ 0

igor_vitrenko [27]

1) The velocity of the particle is given by the derivative of the position. So, if we derive s(t), we get the velocity of the particle as a function of the time:

$v(t)=s'(t)=(2t^3-3t^2-36t+6)'=6t^2-6t-36$

2) The acceleration of the particle is given by the derivative of the velocity. So, if we derive v(t), we get the acceleration of the particle as a function of the time:

$a(t)=v'(t)=(6t^2-6t-36)'=12t-6$

8 0

3 years ago

A conducting sphere of radius R1 carries a charge Q. Another conducting sphere has a radius R2 = 3 4 R1, but carries the same ch

Blizzard [7]

Answer:

The ratio of electric field is 16:9.

Explanation:

Given that,

Radius $R_{2}=\dfrac{3}{4}R_{1}$

Charge = Q

We know that,

The electric field is directly proportional to the charge and inversely proportional to the square of the distance.

In mathematically term,

$E=\dfrac{kQ}{R^2}$

Here, $E\propto\dfrac{1}{R^2}$

We need to calculate the ratio of electric field

Using formula of electric field

$\dfrac{E_{2}}{E_{1}}=\dfrac{R_{1}^2}{R_{2}^2}$

Put the value into the formula

$\dfrac{E_{2}}{E_{1}}=\dfrac{(4R_{1})^2}{(3R_{1})^2}$

$\dfrac{E_{2}}{E_{1}}=\dfrac{16}{9}$

Hence, The ratio of electric field is 16:9.

5 0

4 years ago

A copper weight weighs 268 N in air and displaces an amount of water weighing 30. N . What is the weight of the copper measured

lutik1710 [3]

I'm not too sure about this question but its weight in water might be 30N because the law of floatation states that a floating object displaces it own weight of fluid.....

4 0

4 years ago

Read 2 more answers