Answer:
21.75 m
Explanation:
t = Time taken for the car to slow down = 0.75 s
u = Initial velocity = 50 m/s
v = Final velocity = 8 m/s
s = Displacement
a = Acceleration
Equation of motion

Acceleration is -56 m/s²

The distance covered in the 0.75 seconds is 21.75 m
Distance is the total length of an object's path. Displacement is the overall change in position, ie. how far an object is from its initial position.
The court is 30 m long, so a path going back and forth once is 60 m long. Going along this path 6 times totals 360 m.
The end point is the same as the starting point, so the displacement is 0 m.
The precision (relative error) of the centripetal force is 1%.
<h3>Relative error</h3>
This is the error in measurement of a variable obtained in comparison with other variables.
F = mv²/r
where;
- F is centripetal force
- m is mass
- v is velocity
- r is radius
F/m = v²/r
F/m = (0.01v)²/(0.01r)
F/m = 0.01v²/r
F/m = 1%(v²/r)
Thus, the precision (relative error) of the centripetal force is 1%.
Learn more about relative error here: brainly.com/question/13370015
<span>a = (v2 - v1)/t= acceleration formula
a = (70 - 0)/7
a = 10 km/hr/sec
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It's better to use as few units as possible.
10 km/hr = 10 km*1000 m/km/(1 hr*3600 sec/hr) = 25/9 m/sec
a= 25/9 m/sec/se</span>