Answer:
We take 20.0 mL of the 1.0 M fruit drink solution and then add 80.0 mL of water to make 100 mL of a 0.2 M fruit drink solution.
Explanation:
Using the rule that: the no. of millimoles of a solution before dilution is equal to the no. of millimoles of the solution after the dilution. (MV) before dilution = (MV) after dilution. M before dilution = 1.0 M, V before dilution = ??? mL. M after dilution = 0.2 M, V after dilution = 100 mL. ∴ V before dilution = (MV) after dilution / M before dilution = (0.2 M)(100 mL) / (1.0 M) = 20.0 mL. So, we take 20.0 mL of the 1.0 M fruit drink solution and then add 80.0 mL of water to make 100 mL of a 0.2 M fruit drink solution
Answer: Halogens are found in group 17, elements F, Cl, Br, I, and At
Explanation:
Answer:
Explanation:
Concepts and reason
This problem is based on the concept of hydrolysis of esters.
An ester is hydrolyzed to a carboxylic acid and an alcohol when treated with aqueous acid or aqueous base. Under alkaline conditions, the carboxylic acid is obtained in the form as its salt.
Fundamentals
Alkaline hydrolysis of ester is done with strong base {\\rm{NaOH}}NaOHand {\\rm{O}}{{\\rm{H}}^ - }OH\u2212acts as nucleophilic reagent. This reaction is reversible, since carboxylate anion has tendency to react with an alcohol and gives back ester.
Step-by-step
Step 1 of 2
Attack of [{ m{O}}{{ m{H}}^ - }]on carbonyl take place as follows resulting formation of tetrahedral intermediate:
\u043e\u043d\u043e\u043d
Explanation | Hint for next step
The {\\rm{O}}{{\\rm{H}}^ - }OH\u2212nucleophile attacks on the electrophilic carbon of an ester {\\rm{C}} = {\\rm{O}}C=O and forms tetrahedral intermediate after breaking the \\pi\u03c0-bond.
Step 2 of 2
Hydrolysis of product formed from step 1 followed by reaction with {\\rm{NaOH}}NaOHis as follows:
The products of the reaction are:
Explanation | Common mistakes
On the reaction of octyl acetate with aqueous sodium hydroxide, the products octyl alcohol and acetate ion are formed after omitting the {\\rm{N}}{{\\rm{a}}^ + }Na+ions.
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They held together by metallic bonds.
Hopefully this has helped! :)