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aksik [14]
3 years ago
15

Number of

Chemistry
1 answer:
Karolina [17]3 years ago
8 0
Mass plus atomic and number

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Which of the following is soluble in water? <br>1-glycerin <br>2-sand<br>3-iron filing<br>4-oil​
sineoko [7]

Answer:

1-glycerin

Explanation:

Hope it helps! :)

4 0
3 years ago
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What is the mass of an object if its height is 10 meters above ground and its gravitational potential energy (GPE) is 3920 Joule
Serjik [45]

Answer:

40

Explanation:

Your trying to find out the meters so your going to divide 3920J by 10 and 9.8

3920/10/9.8

8 0
3 years ago
Calculate the molar solubility of CaF2 in a 0.25 m solution of NaF(aq).
Kipish [7]

Answer:

6.4 × 10^-10 M

Explanation:

The molar solubility of the ions in a compound can be calculated from the Ksp (solubility constant).

CaF2 will dissociate as follows:

CaF2 ⇌Ca2+ + 2F-

1 mole of Calcium ion (x)

2 moles of fluorine ion (2x)

NaF will also dissociate as follows:

NaF ⇌ Na+ + F-

Where Na+ = 0.25M

F- = 0.25M

The total concentration of fluoride ion in the solution is (2x + 0.25M), however, due to common ion effect i.e. 2x<0.25, 2x can be neglected. This means that concentration of fluoride ion will be 0.25M

Ksp = {Ca2+}{F-}^2

Ksp = {x}{0.25}^2

4.0 × 10^-11 = 0.25^2 × x

4.0 × 10^-11 = 0.0625x

x = 4.0 × 10^-11 ÷ 6.25 × 10^-2

x = 4/6.25 × 10^ (-11+2)

x = 0.64 × 10^-9

x = 6.4 × 10^-10

Therefore, the molar solubility of CaF2 in NaF solution is 6.4 × 10^-10M

8 0
3 years ago
How many miles of O2 can be produced by letting 12.00 miles of KC103 react?
Marat540 [252]
 2KClO3 --> 2KClO2 + O2 
    12                               6    (moles) 
The ratio of KClO3 and O2 is 2:1. This means 2 moles of KClO3 can create 1 mole of O2. So 12 moles of KClO3 will create 6 moles of O2. 
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3 years ago
A teaspoon of powdered caffeine can be as deadly as a teaspoon of ricin. <br><br> True or False
Darina [25.2K]

A teaspoon of caffeine is <em>NOT</em> deadly as teaspoon of ricin                                                                                                            

4 0
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