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Rufina [12.5K]
3 years ago
15

294 g of potassium dichromate contains 52 g of chromium and 39 g of potassium. What is the mass percent of oxygen in the compoun

d?
Chemistry
2 answers:
oee [108]3 years ago
7 0

The answer is 69.048%.


Mass of potassium dichromate (K₂Cr₂O₇) is 294 g, which is a 100%.


Given mass of chromium is 52 g. So, the mass percent of chromium in the compound is 17.687%:

52 g : x% = 294 g : 100%

x = 52 ÷ 294 × 100 %

x = 17.687%


Given mass of potassium is 39 g. So, the mass percent of potassium in the compound is 13.265%:

39 g : x% = 294 g : 100%

x = 39 ÷ 294 × 100 %

x = 13.265%


Therefore, the mass percent of oxygen in the compound is 69.048%:

100% - 17.687% - 13.265% = 69.048%.

IgorLugansk [536]3 years ago
3 0
69.047% is the answer to this question
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2 Ag20 →4 Ag + O2 what reaction is this​
Schach [20]

Answer:

Decomposition

Explanation:

hope it helps you

6 0
3 years ago
Combustion analysis of a 13.42-g sample of estriol (which contains only carbon, hydrogen, and oxygen) produced 36.86 g CO2 and 1
meriva

Answer:

C18H24O3

Explanation:

Step 1:

Data obtained from the question. This include the following:

Mass of estriol = 13.42g

Mass of CO2 = 36.86g

Mass of H2O = 10.06g

Molar mass of estriol = 288.38g/mol

Step 2:

Determination of the mass of Carbon (C), Hydrogen (H) and Oxygen (O) present in the compound. This is illustrated below:

For Carbon, C:

Molar mass of CO2 = 12 + (2x16) = 44g/mol

Mass of C in CO2 = 12/44 x 36.86 = 10.05g

For Hydrogen, H:

Molar Mass of H2O = (2x1) + 16 = 18g/mol

Mass of H in H2O = 2/18 x 10.06 = 1.12g

For Oxygen, O:

Mass of O = 13.42 – (10.05 + 1.12) = 2.25g

Step 3:

Determination of the empirical formula for estriol. This is illustrated below:

C = 10.05g

H = 1.12g

O = 2.25g

Divide by their molar mass

C = 10.05/12 = 0.8375

H = 1.12/1 = 1.12

O = 2.25/16 = 0.1406

Divide by the smallest i.e 0.1406

C = 0.8375/0.1406 = 6

H = 1.12/0.1406 = 8

O = 0.1406/0.1406 = 1

Therefore, the empirical formula for estriol is C6H8O

Step 4:

Determination of the molecular formula for estriol. This is illustrated below:

Molecular formula is simply a multiple of the empirical formula i.e

Molecular formula => [C6H8O]n

[C6H8O]n = 288.38g/mol

[(12x6) + (8x1) + 16]n = 288.38

[72 + 8 + 16]n = 288.38

96n = 288.38

Divide both side by 96

n = 288.38/96 = 3

Molecular formula => [C6H8O]n

=> [C6H8O]n

=> [C6H8O]3

=> C18H24O3

Therefore, the molecular formula for estriol is C18H24O3

4 0
3 years ago
What is the specific heat of a substance if a mass of 10.0 kg increases in temperature from 10.0°c to 70.0°c when 2,520 j of hea
LekaFEV [45]

Answer:

0.00420

Explanation:

The equation is Q=mc(T(final)-T(initial), where c is the specific heat, Q is heat supplied, m is mass, T(final) is final temperature and T(initial) is initial temperature (you'll see this written as delta T, which means change in temperature).

2520 = Q

m = 10.0kg; answer choices are in g, not kg, so multiply by 1000 to get m in g; m = 10000 g

Plug in the values you have and solve for c.

2520=(10000)(c)(70-10)

2520=600000c

c=0.0042 j/(gc)

5 0
2 years ago
Read 2 more answers
A 25.0 mL sample of an acetic acid solution is titrated with a 0.175 M NaOH solution. The equivalence point is reached when 37.5
Soloha48 [4]
This is all i know
First of all, let's write the equation of the reaction.
CH₃COOH + NaOH ⇒ CH₃COONa + H₂O
The formula to be used here is CaVa/CbVb = na/nb
where Ca is the concentration of the acid (?)
Cb is the concentration of the base (0.175M)
Va is the volume of the acid (25 mL)
Vb is the volume of the base (37.5 mL)
na is the number of moles of acid (1)
nb is the number of moles of base (1)
Ca × 25/0.175 × 37.5 = 1/1
Ca = 0.175 × 37.5 × 1 /25 ×1
Ca = 0.263 M
The concentration of the acid in the sample was 0.263 M

5 0
3 years ago
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Which of the equations below represents the correct BALANCED equation?
vovikov84 [41]

Answer:

b. Mg (s) + 2HCl (aq) --> MgCl2 (aq) + H2

Explanation:

A subscript applies only to the element it is attached to while coefficients apply to all elements in a compound.

"a" has 1 atom of each element on the left but 2 Cl on the right.

"c" has 2 Mg, 1 H, & 1 Cl on the left but 1 Mg, 2 H, and 2 Cl on the right.

"d" has 2 atoms of each element on the left but only 1 Mg on the right.

"b" is the only answer with equal numbers of atoms on the right and left sides of the equation.

8 0
3 years ago
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