To form the value of 1500 in
scientific notation, it is
<span><span>
1.
</span>By simply
moving the period which separates the whole numbers from the decimal numbers
between 1 and 5. </span>
<span><span>
2.
</span>Thus, it
then becomes 1.5 </span>
<span><span>
3.
</span>Next, is
you have to count how many moves the period made from its point of origin
hence, for this value is 3</span>
<span><span>4.
</span>Therefore,
the scientific notation for the number is 1.5 x 10^3</span>
ιт ιѕ ¢αℓℓє∂ тнє ρα¢ιfι¢ ρℓαтє. ιт ιѕ α σ¢єαиι¢ тє¢σиι¢ ρℓαтє, ιт ℓιєѕ вєиєαтg тgє ρα¢ιfι¢ σ¢єαи
нσρє ι ¢συℓ∂ нєℓρ уσυ συт.
<u>Answer:</u> The sample of Carbon-14 isotope will take 2377.9 years to decay it to 25 %
<u>Explanation:</u>
The equation used to calculate rate constant from given half life for first order kinetics:

where,
= half life of the reaction = 5730 years
Putting values in above equation, we get:

Rate law expression for first order kinetics is given by the equation:
![k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
where,
k = rate constant = 
t = time taken for decay process = ? yr
= initial amount of the sample = 100 grams
[A] = amount left after decay process = (100 - 25) = 75 grams
Putting values in above equation, we get:

Hence, the sample of Carbon-14 isotope will take 2377.9 years to decay it to 25 %
K5O2
convert grams to moles, divide both by the smallest mole mass, multiply that until hole.
30.5 g K ÷ 39.10 = .78 mol
6.24 g O ÷ 16 = .39 mol
.78 mol ÷ .39 mol = 2.5
.39 mol ÷ .39 mol = 1
2.5 x 2 = 5
1 x 2 = 2
K5O2
Answer: 20.775 g S
Explanation: 3.9x10^23 atoms = 0.648 mol
Atomic mass S = 32.08
S in grams = 20.775