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alex41 [277]
3 years ago
11

A container holds 1 mole of helium gas. The volume of the container is 2 liters and the pressure inside the container is 105.0 k

Pa. If the volume of the container is decreased to 1.5 liters, what will be the new pressure inside the container?
Chemistry
1 answer:
andrezito [222]3 years ago
8 0
Your answer is 0.94atm
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What is 1500 in scientific notation
Svet_ta [14]
To form the value of 1500 in scientific notation, it is <span><span>
1.    </span>By simply moving the period which separates the whole numbers from the decimal numbers between 1 and 5. </span> <span><span>
2.    </span>Thus, it then becomes 1.5 </span> <span><span>
3.    </span>Next, is you have to count how many moves the period made from its point of origin hence, for this value is 3</span>
<span><span>4.    </span>Therefore, the scientific notation for the number is 1.5 x 10^3</span>



7 0
3 years ago
What type of boundary exists around the Pacific Ocean?
Otrada [13]

ιт ιѕ ¢αℓℓє∂ тнє ρα¢ιfι¢ ρℓαтє. ιт ιѕ α σ¢єαиι¢ тє¢σиι¢ ρℓαтє, ιт ℓιєѕ вєиєαтg тgє ρα¢ιfι¢ σ¢єαи

нσρє ι ¢συℓ∂ нєℓρ уσυ συт.

4 0
3 years ago
The half-life for the radioactive decay of C-14C-14 is 5730 years. You may want to reference (Pages 598 - 605) Section 14.5 whil
KIM [24]

<u>Answer:</u> The sample of Carbon-14 isotope will take 2377.9 years to decay it to 25 %

<u>Explanation:</u>

The equation used to calculate rate constant from given half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life of the reaction = 5730 years

Putting values in above equation, we get:

k=\frac{0.693}{5730yrs}=1.21\times 10^{-4}yrs^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,

k = rate constant  = 1.21\times 10^{-4}yr^{-1}

t = time taken for decay process = ? yr

[A_o] = initial amount of the sample = 100 grams

[A] = amount left after decay process =  (100 - 25) = 75 grams

Putting values in above equation, we get:

1.21\times 10^{-4}=\frac{2.303}{t}\log\frac{100}{75}\\\\t=2377.9yrs

Hence, the sample of Carbon-14 isotope will take 2377.9 years to decay it to 25 %

8 0
3 years ago
What is the empirical formula of a compound composed of 30.5 g potassium (k) and 6.24 g oxygen (o)?
VLD [36.1K]
K5O2

convert grams to moles, divide both by the smallest mole mass, multiply that until hole.

30.5 g K ÷ 39.10 = .78 mol
6.24 g O ÷ 16 = .39 mol
.78 mol ÷ .39 mol = 2.5
.39 mol ÷ .39 mol = 1
2.5 x 2 = 5
1 x 2 = 2
K5O2

5 0
3 years ago
7.<br> How many grams are contained in 3.9 x 1023 sulfur atoms?<br> atoms → moles<br> grams<br> I
Anni [7]

Answer: 20.775 g S

Explanation: 3.9x10^23 atoms = 0.648 mol

Atomic mass S = 32.08

S in grams = 20.775

4 0
3 years ago
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