Answer:
Since KOH is a strong base, the solution completely ionizes into K+ and OH- when in water. The reaction KOH --> K+ + OH- takes place. The concentration of [ OH- ] can then be used to calculate the pOH of the solution. pH = 14 - pOH = 14 - 1.48 = 12.52
Explanation:
Answer:
d:more dense and falls
Explanation:
warm air Rises around cold air bc of its lower density. and when you have a lower density fluid or sum the lower density fluid rises and the higher density falls
I think thats the answer but feel free to check my work
Answer:
% yield = 62.21 %
Explanation:
- C2H4(g) + H2O(l) → C2H6O(l)
∴ mass C2H4(g) = 4.6 g
∴ mass C2H6O(l) = 4.7 g
- % yield = ((real yield)/(theoretical yield))×100
theretical yield:
∴ molar mass C2H4(g) = 28.05 g/mol
⇒ mol C2H4(g) = (4.6 g)*(mol/28.05 g) = 0.164 mol
⇒ mol C2H6O(l) = (0.164 mol C2H4)*(mol C2H6O(l)/molC2H4(g))
⇒ mol C2H6O(l) = 0.164 mol
∴ molar mass C2H6O(l) = 46.07 g/mol
⇒ mass C2H6O(l) = (0.164 mol)*(46.07 g/mol) = 7.55 g
⇒ theoretical yield = 7.55 g
⇒ % yield = (4.7 g)/(7.55 g))*100
⇒ % yield = 62.21 %
