Answer:
15.75 grams of HNO3 was used and dissolved in 2.5 liters of solvent, to make a 0.10 M solution
Explanation:
Step 1: Data given
Nitric acid = HNO3
Molar mass of H = 1.01 g/mol
Molar mass of N = 14.0 g/mol
Molar mass O = 16.0 g/mol
Number of moles nitric acid (HNO3) = 0.25 moles
Molairty = 0.10 M
Step 2: Calculate molar mass of nitric acid
Molar mass HNO3 = Molar mass H + molar mass N + molar mass (3*O)
Molar mass HNO3 = 1.01 + 14.0 + 3*16.0
Molar mass HNO3 = 63.01 g/mol
Step 3: Calculate mass of solute use
Mass HNO3 = moles HNO3 * molar mass HNO3
Mass HNO3 = 0.25 moles * 63.01 g/mol
Mass HNO3 = 15.75 grams
15.75 grams of HNO3 was used and dissolved in 2.5 liters of solvent, to make a 0.10 M solution
Answer:
Diamagnetism in atom occurs whenever two electrons in an orbital paired equalises with a total spin of 0.
Paramagnetism in atom occurs whenever at least one orbital of an atom has a net spin of electron. That is a paramagnetic electron is just an unpaired electron in the atom.
Here is a twist even if an atom have ten diamagnetic electrons, the presence of at least one paramagnetic electron, makes it to be considered as a paramagnetic atom.
Simply put paramagnetic elements are one that have unpaired electrons, whereas diamagnetic elements do have paired electron.
The atomic orbital and radius increases by gaining electron linearly so even electron numbered atoms are diamagnetic while the odd electron numbered atoms are paramagnetic.
Running through the first 18 elements one can observe that there is an alternative odd number of electrons and an even number proofing that that half of the first 18 elements shows paramagnetism and diamagnetism respectively.
Explanation:
Copper + sulfur create copper sulfide.
It's a lengthy process to find the empirical formula:
Sulfur:

Copper:

S:Cu =>
=>
=> 
The empirical formula would just be 
It is quite easy:
1 cal = 4,1868 J
Solution is:
2930 kcal = 4,1868 * 2930 [kJ] = 12267,324 [kJ]
The concentration of solution : 0.2 M
<h3>Further explanation</h3>
Given
5.6 g Potassium hydroxide(KOH)
500 ml of solution = 0.5 L
Required
The concentration
Solution
Molarity shows the number of moles of solute in every 1 liter of solution or mmol in each ml of solution

MW KOH = 39+16+1=56 g/mol
mol solute(KOH) :
= mass : MW KOH
= 5.6 : 56 g/mol
= 0.1
Molarity :
= 0.1 : 0.5
= 0.2 M