Answer: each plate will experience an electric field strength of 12456.74N/C i.e 12.456 kN/C
Explanation:
Electric field strength E = F/Q
F is force of attraction or repulsion experienced by each charged ring due to the other charged ring
Q is the charge on each ring = 40nC
Also;
F = (QQ) /4¶£d^2
d is the distance between rings = 17cm
QQ = product of their charges
£ = permeability of free space
¶ is pi
From the above E becomes
E = Q/(4¶£d^2) as experienced by each ring.
E = (9*10^9 *40*10^-9) ÷ (17*10^-2)^2
NB 1/(4¶£) = 9*10^9
E = 360÷ 0.0289
E = 12457.74N/C
this is the electric field strength experienced by each ring.
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