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Ilya [14]
3 years ago
9

A 5.00 kilogram block slides along a horizontal,frictionless surface at 10.0 meters per second. for 4.00 seconds. The magnitude

of the blocks momentum is ?
A)200 Kg m/s

B)50.0 Kg m/s

C)20.0 Kg m/s

D)12.5 Kg m/s
Physics
1 answer:
Anna71 [15]3 years ago
3 0
Momentum = Mass * Velocity
                     = 5 kg * 10 m/s = 50 kg m/s.  B
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What constant horizontal force is required to drag a 5 kg block along a
BARSIC [14]

Answer:

25N

Explanation:

formula=> Frictional force= coefficient of friction x normal reaction

normal reaction is mass x gravity(10N/kg)

so Frictional force= 0.5x5x10

=25N

but that is the Frictional force not the constant force

to get the constant force, subtract the Frictional force from the weight of the block

weight= mass x gravity

= 5x10

= 50N

50N-25N

=25N

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How much heat is required to change 70 grams of water to steam at 100°C. (Lv=2.3 × 10^6J/kg)
skad [1K]

Answer:

161000 J

Explanation:

Please do mark as brainliest. Hope this helps! :)

4 0
3 years ago
How does putting a mirror on a sharp bend help to prevent accidents
timofeeve [1]
It allows people to see around the corner and anticipate what speed changes they will need to make
6 0
3 years ago
Read 2 more answers
A plane has a takeoff speed of 88.3 m/s and can accelerate at a rate of 3m/s to reach that speed. How long does the plane take t
Mrrafil [7]

v = \frac{d}{t}

and

a = \frac{v}{t}

We have acceleration and velocity so:

3 = \frac{v}{t}

88.3 = \frac{d}{t}

In the acceleration equation we can isolate for v and then plug it back into the other equation to solve...

So...

3t = v

88.3 = 3t

Divide by three and

t = 29.4 s

3 0
3 years ago
I will give a Brainly to the best answer. Good luck, my good friends!
brilliants [131]
Hi


we know that

density=mass/volume

mass of liquid =6g= 6x10^-3kg.

volume of liquid=12ml=12x10^-3litre


density=6x10^-3/12x10^-3

=.5kg/liter

thanks for asking
3 0
3 years ago
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