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3 years ago

4.Explain what must be true of component waves for reinforcement or interference to occur.

Physics

1 answer:

professor190 [17]3 years ago

7 0

Answer:

The component of waves must have same frequency and phase.

Explanation:

when the component of waves vibrate at the same rate and attain maximum point at the same time, reinforcement of the waves amplitude occur to cause a constructive interference.However, when the two waves are out of phase where one is at minimum when the other is at maximum a destructive interference happens.

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The law of reflection states that if the angle of incidence is 38 degrees, the angle of reflection is ___ degrees.

Tasya [4]

Answer:

Explanation:

because the law of reflection states angle of incidence is equal to the angle of reflection

4 0

3 years ago

Un objeto de 200 gramos está amarrado del extremo de una cuerda y gira describiendo un círculo horizontal de 1.20 m de radio a r

vesna_86 [32]

Answer:

La tensión es 85.3 N.

Explanation:

Cuando el objeto gira en dirección horizontal, la sumatoria de fuerzas se puede calcular usando la segunda ley de Newton:

$\Sigma F_{x} =ma_{c}$

$T = ma_{c}$

Dado que el movimiento es horizontal, el peso (que está en el eje y) no contribuye en la sumatoria de fuerzas en el eje x. Por lo que la única fuerza actuando sobre el objeto en la dirección del movimiento es la tensión.

En donde:

m: es la masa del objeto = 200 g = 0.200 kg

$a_{c}$ : es la aceleración centrípeta

La aceleración centrípeta viene dada por:

$a_{c} = \omega^{2} r$

En donde:

ω: es la velocidad angular del objeto = 3 rev/s

r: es el radio = 1.20 m

Entonces, la tensión es:

$T = m\omega^{2} r = 0.200 kg(3\frac{rev}{s}*\frac{2\pi rad}{1 rev})^{2}*1.20 m = 85.3 N$

Por lo tanto, la tensión es 85.3 N.

Espero que te sea de utilidad!

5 0

2 years ago

A string attached to an airborne kite was maintained at an angle of 40.0 with the ground. if 120m of string was reeled in to ret

AleksAgata [21]

The hypotenuse is measured at 120 meters of string, and you need to solve for the leg of the triangle that is horizontal. The degree is 40, so use trigonometry to figure it out.
Cosin (40) is equal to around .766
Adjacent/Hypotenuse
x/120 = cos40
Answer: 91.92533.
If you use 3 significant figures it should be 91.9 meters.

5 0

3 years ago

If the angle of refraction is 20 degrees what is the angle of incidence

Romashka-Z-Leto [24]

Answer:

13.1

Explanation:

that's what I'm gonna go with, but u can research more

5 0

3 years ago

what will be the moment of inertia of a body if it rotates at a uniform rate of 10rad/sec^2 by a torque of 120Nm?

Naya [18.7K]

Answer:

12 kgm²

Explanation:

here angular acceleration = 10rad/sec²

torque= 120Nm

moment of inertia=?

we know,

torque= angular acceleration× moment of Inertia

or, moment of inertia = torque/angular acceleration

= 120/10

= 12kgm²

7 0

3 years ago