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Tems11 [23]
2 years ago
13

What is the percent yield of O2 if 10.2 g of O2 is produced from the decomposition of 17.0 g of H2O?

Chemistry
2 answers:
yawa3891 [41]2 years ago
5 0

The balanced chemical reaction will be:

2H2O = 2H2 + O2

<span>We are given the amount of water used in the decomposition reaction. This will be our starting point.</span>

<span>17.0 g H2O</span> (1 mol  H2O/ 18.02 g H2O) (1 mol O2/2 mol <span>H2O</span>) ( 32.00 g O2/1mol O2) = 15.09 g O2

Percent yield = actual yield / theoretical yield x 100

<span>Percent yield =10.2 g / 15.09  g x 100</span>

Percent yield = 67.58%

sineoko [7]2 years ago
3 0

Answer: D

Explanation:  67.6

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Give all possible ml values for orbitals that have each of the following: (a) l = 2; (b) n = 1; (c) n = 4, l = 3.
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Answer:

(a) ml = 0, ±1, ±2

(b) ml = 0

(c) ml = 0, ±1, ±2, ±3, ±4

Explanation:

The rules for electron quantum numbers are:

1. Shell number, 1 ≤ n

2. Subshell number, 0 ≤ l ≤ n − 1

3. Orbital energy shift, -l ≤ ml ≤ l

4. Spin, either -1/2 or +1/2

So in our exercise,

(a) l = 2; equivalent with with sublevel <em>d</em>

-l ≤ ml ≤ l, ml = 0, ±1, ±2, equivalent with dxy, dxz, dyz, dx2-y2, dz2

(b) n = 1;

n = 1, only 01 level

l = 0, equivalent with sublevel <em>s</em>

ml = 0

(c) n = 4, l = 3.

l = 3, equivalent with sublevel <em>f</em>

ml = 0, ±1, ±2, ±3, ±4

7 0
3 years ago
How was Bohr’s atomic model different from Rutherford’s atomic model?
Aleks04 [339]

C is the answer.

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Answer:

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Explanation:

1) <u>Initial conditions of the helium gas</u>:

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2) <u>Ideal gas equation</u>:

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3) <u>Solve for n</u>:

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4) <u>At STP:</u>

  • STP stands for standard pressure and temperature.
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