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3 years ago

How many grams of h3po4 are in 255 ml of a 4.50 m solution of h3po4?

1 answer:

7 0

H3PO4 has molecular weight of approximately 98 grams per mole. 4.50 M is equal to 4.50 mole per 1000 mL solution of H3PO4. 255 mL times 4.50 mol /1000 mL times 98 g/mol is equal to 112.455 grams. Note that I automatically equate 1 Liter to 1000 mL since the given volume is in mL for easier computation.

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Is the following chemical equation balanced? 4Al + 3O2 2Al2O3 yes no

PolarNik [594]

Answer:

Yes!

Explanation:

4Al + 3O2 -> 2Al2O3

4 Al's on the left side

6 O's on the left side

4 Al's on the right side

6 O's on the left side

This is balanced! Let me know if you need help with any other equations.

4 0

3 years ago

Read 2 more answers

How do you balance this equation?

Margarita [4]

Answer:

Al4C3 + 12H2O = 3CH4 + 4Al(OH)3

Explanation:

Not sure if any explanation is needed but always start with the most complex compound. In this case it is Al(OH)3. You can see that there is 4 Aluminiums on the other side so I would start by putting a 4 next to the Al(OH)3. This now gives me 12 Hydrogens and 12 Oxygens on the right side. I put a 3 next to the CH4 to balance the Carbons on the left side. This leaves me with 12 Oxygens and 24 Hydrogens on the right side. This ends up being perfect because I can put a 12 next to the H2O.

6 0

3 years ago

Rank the species CH2NH, CH3I, HF, C2H6 from most to least miscible in ammonia (NH3) 1. CH3I > C2H6 > HF > CH2NH 2. CH2N

777dan777 [17]

Answer:

$HF>CH_{2}NH>CH_{3}I>C_{2}H_{6}$

Explanation:

$NH_{3}$ is an weak base. HF is an weak acid. Hence an acid-base reaction will ocuur between $NH_{3}$ and HF resulting a homogeneous mixture.

$NH_{3}$ is a polar protic molecule. Hence it can form hydrogen bonding with another polar protic molecule $CH_{2}NH$ . Also dipole-dipole attraction force along with london dispersion force exists between $CH_{2}NH$ and $NH_{3}$ .

$CH_{3}I$ is a polar molecule. Hence only dipole-dipole attraction force along with london dispersion force operates between $CH_{3}I$ and $NH_{3}$ .

$C_{2}H_{6}$ is a non-polar molecule. Hence only london dispersion force exists between $C_{2}H_{6}$ and $NH_{3}$ .

So, order of miscibility: $HF>CH_{2}NH>CH_{3}I>C_{2}H_{6}$

(most) (least)

5 0

3 years ago

"how a trait appears, or is physically expressed?

grin007 [14]

I think the answer is genotype.

6 0

3 years ago

BRAINLIESTTT ASAP!! PLEASE HELP ME ASAP!

Alexandra [31]

Answer:

Single displacement and reduction

Explanation:

In a single-displacement reaction, one element exchanges partners with another.

$\rm Ca + 2H$_2$O $\longrightarrow$ Ca(OH)$_2$ + H$_2$$

This is a single-displacement reaction, because the element Ca exchanges partners with H.

This is also a reduction/oxidation (redox) reaction, because the optically active of Ca increases from 0 to +2 (oxidation), while the oxidation number of H decreases from +1 to 0 (reduction),

The most common types of reactions are:

Combination
Decomposition
Single displacement
Double displacement
Reduction/oxidation

4 0

3 years ago