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Taya2010 [7]
2 years ago
7

If a car changes ita velocity from 32km/hr to 54km/hr in 8.0 seconds, what is its acceleration

Physics
1 answer:
Andrews [41]2 years ago
7 0
Firstly, let's convert the velocities in km/hr to m/s
32*1000/3600=8.89m/s
54*1000/3600=15m/s
From the formula, acceleration=V-U/t
15-8.89/8=0.76m/s²
hope this helps.
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Answer:

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Explanation:

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angle = 34°

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Question)

from the projectile motion the horizontal distance traveled by electron is

x = u×cosA×t

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F = qE

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By newton 2nd law of motion

ma = qE

⇒a = qE/m

Also, y = u×sinA×t - 0.5×a×t^2

⇒y = u×sinA×t - 0.5×(qE/m)×t^2

if y = 0 then

⇒t = 2mu×sinA/(qE) = x/(u×cosA)

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Now plugging the values we get

E = 2×9.1×10^{-31}×3.6^2×10^{12}×(sin34°)×(cos34°)/(1.5×10^{-2}×(-1.6)×10^{-19})

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3 years ago
Tangential velocity 2. Parabolic pathway 3. Projectile 4. Centripetal acceleration 5. Centripetal force a. acceleration towards
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1. Tangential velocity:

<em>e) the instantaneous velocity of a body moving in a circular path.</em>

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<em>c. a curved path followed by projectiles</em>

3. Projectile

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4. Centripetal acceleration

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